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Marta_Voda [28]
2 years ago
7

A glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.50 x 105 P

a. Assuming that the top and bottom surfaces of the cap each have an area of 4.40 x 10-4 m2, obtain the magnitude of the force that the screw thread exerts on the cap in order to keep it on the bottle. The air pressure outside the bottle is one atmosphere
Physics
1 answer:
MArishka [77]2 years ago
4 0

Answer:

F \approx 19.5 N

Explanation:

From the question we are told that:

Pressure of  P_{CO_2}=1.50 * 105 Pa.

Bottle cap area A_b= 4.40 * 10-4 m^2

 

Generally the equation for Resultant pressure P_r is give as is mathematically given by

P_r=P_{CO_2}-P_a

Where

P_a=atmospheric\ pressure = 1.013*10^5 pa

P_r=1.50 * 105 Pa-1.013*10^5 pa

P_r=0.487*10^5 pa

Generally the equation for Force exerted by screw F is give as is mathematically given by

F = P*A\\F = 0.487*10^5*4.00*10^-4\\ F = 19.48 N

F \approx 19.5 N

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A 14.0 m uniform ladder weighing 490 N rests against a frictionless wall. The ladder makes a 63.0°-angle with the horizontal.
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position of firefighter r_F = 3.8m

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angle of ladder \alpha = 63

Unknown:

force of the wall on the ladder F_W

force of friction on base of ladder F_R

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From the free body diagram of the sketch you get 3 equations:

F_x = ma_x = F_W - F_R = 0\\ F_y = ma_y = F_N - F_F - F_L = 0\\ \tau _P = \overrightarrow{r} \times \overrightarrow{F} = r_FF_Fcos\alpha + \frac{1}{2}r_LF_Lcos\alpha - r_LF_Wsin\alpha = 0

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a)

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F_R = \mu F_N\\ \mu = \frac{F_R}{F_N} \\ \mu = 0.3

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In Thomson's model, an atom comprises of electrons that are surrounded by a group of positive particles to equal the electron's negative particles, like negatively charged “plums” that are surrounded by positively charged “pudding”.

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