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zzz [600]
1 year ago
10

What is the difference between engineering controls and administrative controls?

Physics
1 answer:
nadezda [96]1 year ago
5 0

Engineering controls could involve altering the weight of the products, adjusting the heights of the work surfaces, or getting lifting equipment. Administrative controls are workplace policies, practices, and processes that reduce the likelihood of risky situations for employees.

<h3>What are Engineering controls?</h3>
  • Engineering controls are methods for preventing dangerous situations for workers by erecting a barrier between them and the danger or by ventilating the area to remove any hazardous materials.
  • Instead of depending on employee behavior or mandating that employees wear safety gear, engineering controls entail making physical changes to the workplace itself.
<h3>What is Administrative controls?</h3>
  • Administrative controls are policies, procedures, shift designs, or training that reduce the threat of a hazard to a person.
  • Typically, administrative controls aim to alter people's behavior (such as that of manufacturing workers) rather than eliminating the real risk or provide personal protective equipment (PPE).

Learn more about Administrative controls here:

brainly.com/question/17628591

#SPJ4

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Two states of matter are described below. State A: Cannot be compressed and retains its shape State B: Highly compressible Which
telo118 [61]

Answer:

State A = piece of metal; State B = air

Explanation:

For the three main states of matter here's how it breaks down.

Solid - Cannot be compressed and retains its shape

Liquid - Cannot be compressed and does not retain its shape

Gas - Compressible and does not retain its shape.

Knowing this State A has to be solid.  Only one of the options has A as a solid, so that's the answer.   Worth knowing state B is a gas though, only one compressible, just like solid is the only one that retains its shape.

7 0
3 years ago
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Instead of rolling down the ramp over the step, imagine the ball falls off the back of the ramp directly to the ground. What is
lesya692 [45]

0J

According to the law of conservation of energy, the potential energy is converted to kinetic energy. Remember, potential energy is calculated using height and weight. If the ball is on the ground, height is 0.

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3 years ago
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Under which conditions are particles in a medium said to be in phase with one another?
rewona [7]

Answer:

Corvette Corvette

Explanation:

teehee

The answer is A btw :)

7 0
3 years ago
The linear charge density on the inner conductor is and the linear charge density on the outer conductor is
Lubov Fominskaja [6]

Complete Question

The complete question is  shown on the first uploaded image (reference for Photobucket )

Answer:

The  electric field is  E = -1.3 *10^{-4} \ N/C

Explanation:

 From the question we are told that

    The linear charge density on the inner conductor is  \lambda _i  =  -26.8 nC/m  =  -26.8 *10^{-9} C/m

    The linear charge density on the outer conductor is

  \lambda_o  = -60.0 nC/m  =  -60.0 *10^{-9} \ C/m

     The position of interest is r =  37.3 mm =0.0373 m

Now this position we are considering is within the outer conductor so the electric field  at this point is due to the inner conductor (This is because the charges on the conductor a taken to be on the surface of the conductor according to Gauss Law )

Generally according to Gauss Law

         E (2 \pi r l) =  \frac{ \lambda_i }{\epsilon_o}

=>    E =  \frac{\lambda _i }{2 \pi *  \epsilon_o * r}

substituting values  

       E =  \frac{ -26 *10^{-9} }{2 * 3.142 *  8.85 *10^{-12} * 0.0373}

       E = -1.3 *10^{-4} \ N/C

The  negative  sign tell us that the direction of the electric field is radially inwards

    =>   |E| = 1.3 *10^{-4} \ N/C

5 0
3 years ago
I need help solving both of the questions fast please!!!!!!
sergey [27]
I haven´t learned that yet I´m sorry.
6 0
3 years ago
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