9514 1404 393
Answer:
(B) 4
Step-by-step explanation:
Consider the units column. The only sum of 3 and a single digit that will end in 1 is the sum ...
3 + 8 = 11
This tells you A = 8, so the top number is 1983, and the middle number is B78.
Considering the first two columns, we know that 83 +78 = 161, so there must be a carry of 1 into the third column. That makes it have the sum ...
1 + 9 + B = <something ending in 4>
We know the something cannot be 04 or 24, so must be 14. Then ...
10 + B = 14 ⇒ B = 4
__
So, the whole sum is ...
1983 +478 = 2461
and the letter values are ...
Hello There!
The first one seems alright.
The second one it would be 1/2.
This is because half of the options have “R” on them.
Given that <span>C = { X | X + 6 = 10}
This can be interpreted grammatically as "C is a set X such that X is the solution to X + 6 = 10".
Given that X + 6 = 10
X = 10 - 6 = 4
Therefore, the solution is
C = {4}
</span>
Answer:
m=1/300 du
Step-by-step explanation:
we have that m=∫∫rho(x,y)dA for this we must find the limits of integration (according to the graph1)
On the x axis: if y=2x and x+2y=1 then y=2x and y=(1-x)/2 ⇒ 2x=(1-x)/2 ⇒ 4x=1-x ⇒ 5x=1 ⇒ x=1/5; on the y axis y=0 and y=1/2
m=∫∫rho(x,y)dA (view the graph 2)
