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seraphim [82]
3 years ago
10

Base of a triangle is 15 height is 7 what is area of triangle

Mathematics
1 answer:
eimsori [14]3 years ago
8 0

Answer:

b·h=105

Step-by-step explanation:

u multiply the base times the height

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Homework Help ASAP!
lutik1710 [3]

Answer:

The statement is true

Step-by-step explanation:

The denominators of the fractions are 3 and 4. The least common multiple of those numbers is 12, making the least common denominator 12.

5 0
3 years ago
Nancy's garden has the dimensions shown 4 1/2 yard<br><br> 3 3/4 yd . She need find the area
Marina86 [1]

Answer:

The area of Nancy's garden is 16\frac{7}{8}\ yd^{2}

Step-by-step explanation:

I assume that the Nancy's garden is a rectangle shape

To find the area first convert mixed number to an improper fraction

4\frac{1}{2}\ yd=\frac{4*2+1}{2}=\frac{9}{2}\ yd

3\frac{3}{4}\ yd=\frac{3*4+3}{4}=\frac{15}{4}\ yd

Therefore

The area is equal to

A=\frac{9}{2}*\frac{15}{4}=\frac{135}{8}\ yd^{2}

convert to mixed number

\frac{135}{8}\ yd^{2=\frac{128}{8}+\frac{7}{8}=16\frac{7}{8}\ yd^{2}

4 0
3 years ago
Help me with this urgent due in 5 min​
solniwko [45]

Answer:

The last option

Step-by-step explanation:

4 0
2 years ago
If sinA+cosecA=3 find the value of sin2A+cosec2A​
Irina18 [472]

Answer:

\sin 2A + \csc 2A = 2.122

Step-by-step explanation:

Let f(A) = \sin A + \csc A, we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

\csc A = \frac{1}{\sin A} (1)

\sin^{2}A +\cos^{2}A = 1 (2)

Now we perform the operations: f(A) = 3

\sin A + \csc A = 3

\sin A + \frac{1}{\sin A} = 3

\sin ^{2}A + 1 = 3\cdot \sin A

\sin^{2}A -3\cdot \sin A +1 = 0 (3)

By the quadratic formula, we find the following solutions:

\sin A_{1} \approx 2.618 and \sin A_{2} \approx 0.382

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

\sin A \approx 0.382

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

A \approx 22.457^{\circ}

Then, the values of the cosine associated with that angle is:

\cos A \approx 0.924

Now, we have that f(A) = \sin 2A +\csc2A, we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:

\sin 2A = 2\cdot \sin A\cdot \cos A (4)

\csc 2A = \frac{1}{\sin 2A} (5)

f(A) = \sin 2A + \csc 2A

f(A) = \sin 2A +  \frac{1}{\sin 2A}

f(A) = \frac{\sin^{2} 2A+1}{\sin 2A}

f(A) = \frac{4\cdot \sin^{2}A\cdot \cos^{2}A+1}{2\cdot \sin A \cdot \cos A}

If we know that \sin A \approx 0.382 and \cos A \approx 0.924, then the value of the function is:

f(A) = \frac{4\cdot (0.382)^{2}\cdot (0.924)^{2}+1}{2\cdot (0.382)\cdot (0.924)}

f(A) = 2.122

8 0
3 years ago
Soon you will determine the right triangle connection the pythagorean theorem
Softa [21]
I don't know I just need the points Lol sorry
6 0
2 years ago
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