Plz help mee look at the picture thanks

Mathematics

1 answer:

Degger [83]3 years ago

3 0

Answer:

The answer is D for this question. The one at the very bottom of the picture. The other person who answered on this question is incorrect.

Step-by-step explanation:

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AysviL [449]

Answer:

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Step-by-step explanation:

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3 years ago

Louis’s bill from dinner at a restaurant is $27.62 before tax. The local tax rate is 7.5%. Louis would like to leave a 20% tip o

shtirl [24]

As Louis is only leaving a 20% tip on the pretax bill, this means he's leaving 20% of $27.62
The best thing to do is to find 10% and double it.
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Hope this helps :)

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2 years ago

I dont understand this

kirza4 [7]

Step-by-step explanation:

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3 years ago

Who can solve this 3(35+x)

Studentka2010 [4]

answer: 105+3x

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5 0

2 years ago

Read 2 more answers

Please help I am so lost!!!

ASHA 777 [7]

$\bf tan\left( \frac{x}{2} \right)+\cfrac{1}{tan\left( \frac{x}{2} \right)}\\\\
-----------------------------\\\\
tan\left(\cfrac{{{ \theta}}}{2}\right)=
\begin{cases}
\pm \sqrt{\cfrac{1-cos({{ \theta}})}{1+cos({{ \theta}})}}
\\ \quad \\

\cfrac{sin({{ \theta}})}{1+cos({{ \theta}})}
\\ \quad \\

\boxed{\cfrac{1-cos({{ \theta}})}{sin({{ \theta}})}}
\end{cases}\\\\$

$\bf -----------------------------\\\\
\cfrac{1-cos(x)}{sin(x)}+\cfrac{1}{\frac{1-cos(x)}{sin(x)}}\implies \cfrac{1-cos(x)}{sin(x)}+\cfrac{sin(x)}{1-cos(x)}
\\\\\\
\cfrac{[1-cos(x)]^2+sin^2(x)}{sin(x)[1-cos(x)]}\implies 
\cfrac{1-2cos(x)+\boxed{cos^2(x)+sin^2(x)}}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{1-2cos(x)+\boxed{1}}{sin(x)[1-cos(x)]}\implies \cfrac{2-2cos(x)}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{2[1-cos(x)]}{sin(x)[1-cos(x)]}\implies \cfrac{2}{sin(x)}\implies 2\cdot \cfrac{1}{sin(x)}\implies 2csc(x)$

4 0

3 years ago