The average maximum and minimum values of a formula
We're told (5,-2) is on the line, that's x=5, y=-2
First one y-5 = -7, (x+2)/3=7/3, not equal
Second one y+5=3, (x-2)/3=1, not equal
Third one y+2=0, (x-5)/3=0, TRUE, equal
Fourth one, y-2=-4 (5+5)/3=10/3, not equal
Answer: third choice y+2 = (1/3)(x+5)
The answer is umu( M + m )
In the second equation you are given what Y equals, which is (-5x - 3). You would use this equation and plug it into the y value given in the first equation where it says 2y and solve
That would be
3x - 2(-5x - 3) = -6
3x + 10x + 6 = -6
3x + 10x = -6 - 6
13x = -12
X = -12/13
Then if you want to solve for Y you can use any equation and plug in the x-value found.
I’m going to use equation 2.
Y = -5x - 3
Y = -5(-12/13) - 3
Y = 4.615 - 3
Y = 1.615
(-12/13, 1.615)
Therefore the x-value is -12/13 and the y-value is 1.615.
