Answer:
a) possible progressions are 5
b) the smallest and largest possible values of the first term are 16 and 82
Step-by-step explanation:
<u>Sum of terms:</u>
- Sₙ = n/2(a₁ + aₙ) = n/2(2a₁ + (n-1)d)
- S₂₀ = 20/2(2a₁ + 19d) = 10(2a₁ + 19d)
- 2020 = 10(2a₁ + 19d)
- 202 = 2a₁ + 19d
<u>In order a₁ to be an integer, d must be even number, so d = 2k</u>
- 202 = 2a₁ + 38k
- 101 = a₁ + 19k
<u>Possible values of k= 1,2,3,4,5</u>
- k = 1 ⇒ a₁ = 101 - 19 = 82
- k = 2 ⇒ a₁ = 101 - 38 = 63
- k = 3 ⇒ a₁ = 101 - 57 = 44
- k = 4 ⇒ a₁ = 101 - 76 = 25
- k = 5 ⇒ a₁ = 101 - 95 = 16
<u>As per above, </u>
- a) possible progressions are 5
- b) the smallest and largest possible values of the first term are 16 and 82
Answer:
the answer is 95.0 i took the quiz Yesturday.
Step-by-step explanation:
Answer:
the answer would be B
Step-by-step explanation:
for the slope you would need to count up then over between the two points and do that until you reach where the line crosses or in this case would cross for the y-intercept
Answer:
The numbers are 2 , 4 , 6 or 6 , 4 , 2
Step-by-step explanation:
For solution kindly refer to the attachment .
<u>Related</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u><u> </u>
• The sum of n terms of an AP is ,
=> S = n/2 [ 2a + ( n - 1 ) d ]
• The nth term of an AP is ,
=> T_n = a + ( n - 1 ) d
The formula is y=mx+4 but I forgot how to do it
