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Ronch [10]
3 years ago
12

Together Cam and Brian had 24 pair of jeans. Cam had 4 less the Brian. Which inequality of equation could be used to find the nu

mber of jeans that Brian had?
Mathematics
1 answer:
EleoNora [17]3 years ago
3 0

Answer:

Brian had 4 jeans

Step-by-step explanation:

Together Cam and Brian had 24 pair of jeans. Cam had 4 less the Brian. Which inequality of equation could be used to find the number of jeans that Brian had?

Let the number of jeans

Cam had = x

Brian had = y

Hence: x + y= 24 Jeans

Cam had 4 less the Brian.

= x = y - 4

Hence:

x > y

The number of jeans Brian had is calculated as:

x + y= 24

y - 4 + y= 24

2y = 24+ 4

2y = 28

y = 28/2

y = 14 jeans

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3 years ago
After you add both sides by 9. How can you solve for 5z in this equation <br> 5z-3=12
lutik1710 [3]

Answer:

OPTION A: Divide both the sides by 5

Step-by-step explanation:

We are given:  5z - 3 = 12

When we add 9 to both sides we get:

5z - 3 + 9 = 12 + 9

⇒ 5z + 6 = 21

⇒ 5z = 21 - 6 = 15

⇒ 5z = 15

To find the value of z we have to divide both the sides by 5.

i.e., $ \frac{5z}{5} = \frac{15}{5} $

⇒ z = 3.

3 0
3 years ago
Solve 4 by 216 raise to minus 2 by 3 + 1 by 256 raise to 3 by 4 + 2 by 243 raise to 1 by 5​
olchik [2.2K]

Answer:

214....

Step-by-step explanation:

If the question is : solve 4 by 216 raise to minus 2 by 3 + 1 by 256 raise to minus 3 by 4 + 2 by 243 raise to minus 1 by 5​

The given expression can be written as:

4/(216)-2/3+1/(256)-3/4+2/(243)-1/5

This expression has three terms.

Notice that the exponents are negative:

We will change the division into multiplication so that the exponents will become positive;

4*(216)^2/3+ 1*(256)^3/4+ 2*(243)^1/5

If we multiply 6 three times it will give us 6^3=6*6*6=216

If we multiply 4 four  times it will give us 4^4=4*4*4*4=256

If we multiply 3 five times it will give us 3^5=3*3*3*3*3=243

So we will write it as:

=4*(6^3)^2/3+ 1(4^4)3/4 +2(3^5)^1/5

=4(6)^2+(4)^3+2(3)

=4*36+64+6

=144+64+6

=214

The answer is 214....

7 0
3 years ago
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