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baherus [9]
3 years ago
10

What are the steps −2(x+6)=4(2x−12)+2

Mathematics
1 answer:
Tema [17]3 years ago
3 0

Answer:

first, you distribute

-2x-12=8x-48+2

then, you combine like terms

-2x-12=8x-46

next, you subtract 8x from both sides

-2x-8x-12=-46

You add 12 to both sides.

-10x=-34

finally, you divide -10 from both sides

x=34/10 or x=17/5

Step-by-step explanation:

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butalik [34]
According to the law of sines:

\frac{a}{sin(A)} = \frac{b}{sin(B)}

Using the given values, we can find the angle B and find the number of possible triangles that can be formed.

\frac{2}{sin(75)}= \frac{3}{sin(B)} \\  \\ 
sin(B)=3* \frac{sin75}{2}  \\  \\ 
sin(B)=1.45 \\  \\ 
B=sin^{-1} (1.45)

The range of sin is from -1 to 1. The above expression does not yield any possible value of B, as sin of no angle can be equal to 1.45.

Therefore, we can conclude that no triangle exists with the given conditions.
5 0
3 years ago
X^2-x+2=0<br> Please use the quadratic formula
Ainat [17]

Answer:

\boxed{\sf x=\cfrac{1\pm \sqrt{-7} }{2}}

Step-by-step explanation:

\sf x^2-x+2=0

<u>Use quadratic formula:</u>

\boxed{\sf \frac{-b\pm \sqrt{b^2-4ac}}{2a}}

\sf a=1, b=-1, c=2

___________________________

\sf x_1,_2=\cfrac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\times \:1\times \:2}}{2\times \:1}

  • \sf \sqrt{\left(-1\right)^2-4\times \:1\times \:2}
  • \sf =\sqrt{-7}

_________________

\sf x_1,_2\cfrac{-\left(-1\right)\pm \sqrt{-7}}{2\times \:1}

  • \sf -(-1)=1
  • 2\times 1=2

\sf x_1,_2=\cfrac{1\pm \sqrt{-7} }{2}

_______________________________________

<u>Learn more: brainly.com/question/22286698</u>

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2 years ago
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Mousy=m
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Solve for y.<br> 3X+2y=12
Montano1993 [528]
3x + 2y = 12

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