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erik [133]
3 years ago
15

Which girl can become my friend​

Mathematics
1 answer:
katrin2010 [14]3 years ago
6 0

Answer:

I can be your friend

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Answer:

1

Step-by-step explanation:

-2 1/2 - (-3 1/2) = 1

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Simplify to create an equivalent expression.<br> 2 – 4(5p + 1)
Ganezh [65]

Answer:

A. -20p - 2

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property

<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

2 - 4(5p + 1)

<u>Step 2: Simplify</u>

  1. Distribute -4:                    2 - 20p - 4
  2. Combine like terms:        -20p - 2
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3 years ago
Use euler's theorem to find a number x between 0 and 28 with x85 congruent to 6 modulo 35.
Elan Coil [88]
Problem: find 0 &le; x &le; 28 such that x^85 ≡ 6 modulo 35.

By Fermat-Euler theorem:
If a and n are coprime, i.e. (a,n)=1, then
a^phi(n) ≡ 1 mod n  
where phi(n)=totient function, the number of positive integers less than n that is coprime with n.

for n=35, phi(35)=24 calculated as follows:
There are 10 positive integers from 1 to 34 which are NOT coprime with 35, namely {5,7,10,14,15,20,21,25,28,30}.Therefore phi(35)=34-10=24

From Fermat-Euler theorem, 
x^(phi(35) = x^24 ≡ 1 modulo 35  since (24,35)=1, i.e. 24 and 35 are coprime.
=>
x^12 ≡ &pm; 1 modulo 35. ...........(1)

and 

x^85 ≡ x^(85-3*24) ≡ x^(85-72) ≡ x^(13) ≡ 6 mod 35 ............(2)

Substituting (1) in (2)
x^(12)*x ≡ 6 mod 35
=>
(+1)*x = 6 mod 35   or  (-1)*x ≡ 6 mod 35
x ≡ 6 mod 35           x ≡ -6 mod 35   (rejected)

=>  x=6 

So

6^85 ≡ 6 mod 35


If any clarifications are needed or if you find any errors, please post.
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