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Blizzard [7]
3 years ago
15

ms D ARRIVED AT SCHOOL AT 7:30 AM, SHE SPENT 35 MINUTES AT THE DINNER WITH A FRIEND IT TAKES HER 15 MINUTES TO GET TO SCHOOL WHA

T TIME DID MS D LEFT
Mathematics
1 answer:
Effectus [21]3 years ago
6 0

Answer:

Ms D left at 6:40 AM

Step-by-step explanation:

Given:

MS D arrived at school at 7:30 AM

time spent for dinner = 35 mins

Time taken to to go to school = 15 mins

We will first find the Total time taken after leaving.

Total time taken can be calculated by adding time spent for dinner and Time taken to to go to school.

Total time taken after leaving = time spent for dinner + Time taken to to go to school = 35 +15 = 50 mins

MS D arrived at school at 7:30 AM.

Hence Time Ms D left  = Time She arrive at school - Total time taken after leaving = 7 hrs 30 min - 50 mins = 6 hrs 40 mins.

Hence Ms D left at 6:40 AM.

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SVEN [57.7K]
If x + y = 6, then solve for y to get: y = 6 - x.

Now replace y with 6 - x in both equations.

(5x)/3 + 6 - x = c

2(6 - x) = c - 4x

The upper equation is solved for c.
Now we solve the lower equation for c.

c = 2(6 - x) + 4x

c = 12 - 2x + 4x

c = 2x + 12

Since we have two equations solved for c, we substitute to get

(5x)/3 + 6 - x = 2x + 12

This is an equation in only x, so we can solve for x.

(5x)/3 - 3x = 6

5x - 9x = 18

-4x = 18

x = -9/2

Now we solve for y.

x + y = 6

-9/2 + y = 6

y = 9/2 + 12/2

y = 21/2

Now we solve for c.

c = (5x)/3 + y

c = (5 * (-9/2))/3 + 21/2

c = -45/6 + 21/2

c = -15/2 + 21/2

c = 6/2

c = 3

Answer: c = 3
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3 years ago
Is 152 points in 8 games<br> 171 points in 9 games equivalent
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Answer:

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3 years ago
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