First let's talk about the blue line.
You can see its rising so its slope is certainly positive. But by how much is it rising? You can observe that each unit it rises it goes 1 forward and 1 up so its slope is the ratio of 1 up and 1 forward which is just 1.
We have thusly,

Now look at where blue line intercepts y-axis, -1. That is our n.
So the blue line has the equation of,

Next the black lines. The black lines are axes so their equations are a bit different.
First let's deal with x-axis, does it have slope? Yes but it is 0. The x-axis is still, not rising nor falling. Where does x-axis intercept y-axis? At 0. So the equation would be,

Now we have y-axis. Does y axis have a slope? Yes but it is
. The y-axis rises infinitely in no run. Where does it intercept y-axis? Everywhere! So what should the equation be? What if we ask where does y-axis intercept x-axis and write its equation in terms of x. Y-axis intercepts x-axis at 0 which means its equation is,

That is, every point of a form
lies on y-axis.
Hope this helps :)
They are both equal because the zeros don't count after the number 5.
Answer:
4±√5
EXPLAINED ANSWER:
Since the variable is a binomial and it is squared, we apply square root on both side, and apply the ± sign on the right side (since the solution of a square root can be both positive and negative), and later pass the 4 positive to the other side.
√25 can be (5)(5) or (-5)(-5)
Answer: Gear 14 or 14.3
Step-by-step explanation:
Answer:
The value of x = 11 and y = 2
Step-by-step explanation:
Given : parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, and OP = (2x – 1) m.
We have to find values of x and y.
Let P be the point of intersection of diagonals OM and LN.
In a parallelogram diagonal bisects at right angles and point of intersection divide diagonal in equal parts.
Thus, OP = MP and LP = PN
OP = MP , substitute the values, we get,
(2x-1) = 21
⇒ 2x = 22
⇒ x = 11
LP = PN , substitute the values, we get,
y + 3 = 3y -1
⇒ 3y - y = 4
⇒ 2y = 4
⇒ y = 2
Thus, the value of x = 11 and y = 2