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grandymaker [24]
3 years ago
12

..........................

Mathematics
2 answers:
Norma-Jean [14]3 years ago
4 0

Answer:

..........

Step-by-step explanation:

.......hey :)

Masteriza [31]3 years ago
4 0
Helllllllooooooooooooooooooo.................................
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1 Shannon runs at a constant rate. She can run 3 miles in 26 minutes. What distance, Y in miles, can she run in 15 minutes, x?
Crazy boy [7]

Answer:

1,75 miles

Step-by-step explanation:

3 miles ______26 minutes

1 miles =>26 :3 =8,5 (8 minutes and 5 seconds)

15:8,5 =1,75 miles

7 0
2 years ago
Describe parallelograms in 5 sentence
mixer [17]

Answer:

Their lines never touch. They have 2 different sides. They are like a square but differen. They always have even number.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
please Order least to greatest -2 3/10, -2 2/5, -2 -2 1/2, -3 And yes those are negative signs
rewona [7]
-3; -2 3/10; -2 2/5; -2 1/2

Your welcome!
5 0
3 years ago
Read 2 more answers
In doing so, you collect a random sample of 50 salespersons employed by his company, which is thought to be representative of sa
Deffense [45]

Answer:

z=\frac{0.36 -0.45}{\sqrt{\frac{0.45(1-0.45)}{50}}}=-1.279  

p_v =P(z

And we can use the following code to find it  "=NORM.DIST(-1.279,0,1,TRUE)"

Step-by-step explanation:

Assuming this complete problem: "The CEO of a software company is committed to expanding the proportion of highly qualified women in the organization's staff of salespersons. He believes that the proportion of women in similar sales positions across the country is less than 45%. Hoping to find support for his belief, he directs you to test

H0: p .45 vs H1: p < .45.

In doing so, you collect a random sample of 50 salespersons employed by his company, which is thought to be representative of sales staffs of competing organizations in the industry. The collected random sample of size 50 showed that only 18 were women.

Compute the p-value associated with this test. Place your answer, rounded to 4 decimal places, in the blank. For example, 0.3456 would be a legitimate entry."

1) Data given and notation

n=50 represent the random sample taken

X=18 represent the number of women in the sample selected

\hat p=\frac{18}{50}=0.36 estimated proportion of women in the sample

p_o=0.45 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion of women is less than 0.45:  

Null hypothesis:p\geq 0.45  

Alternative hypothesis:p < 0.45  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.36 -0.45}{\sqrt{\frac{0.45(1-0.45)}{50}}}=-1.279  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z

And we can use the following code to find it  "=NORM.DIST(-1.279,0,1,TRUE)"

4 0
3 years ago
A garrison of 400men had food for 40days.After 10 days,200 more men joined them .How long will the food last now?(Assume that th
mestny [16]

Let x be the amount of food needed for one man for one day. At the beginning, we have enough food for 400 men for 40 days, i.e.

400\cdot 40\cdot x = 16000x

After 10 days, the 400 men will have consumed

400\cdot 10\cdot x = 4000x

food, impliying that the food remaining is

16000x-4000x=12000x

If 200 more men join the garrison, there are now 600 men. Each of them requires x food each day, and there are 12000x units of food remaining. They will last

\dfrac{12000x}{600}=20 days.

6 0
3 years ago
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