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3 years ago

A. 122pi units^3 B. 336pi units^3 C. 56pi units^3 D. 168pi units^3

Mathematics

2 answers:

Alex787 [66]3 years ago

7 0

Answer:

C because I saw this in class before some other kid said C and she was right

Lelu [443]3 years ago

6 0

Answer:the answer is A.

Step-by-step explanation:ap e.x

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Scrieti rezultatul sub forma de fractie ireductabila : a)1/4+5/4; b) 23/17+11/17;c) 16/93+15/93;11/14+23/14;3/16+ 15/16 ; 1 1/8+

Alborosie

Answer:

See explanations below

Step-by-step explanation:

a) 1/4+5/4

= (1+5)/4

= 6/4

= 3/2

b) 23/17+11/17

= (23+11)/17

= 34/17

= 2

c) 16/93+15/93

= (16+15)/93

= 31/93

= 1/3

d) 11/14+23/14

= (11+23)/14

= 34/14

= 17/7

e) 3/16+15/16

= (3+15)/16

= 18/16

= 9/8

f) 1 1/8 + 1 3/8

= 9/8 + 11/8

= (9+11)/8

= 20/8

= 5/2

g) 1 3/10+3 1/10;

= 13/10+31/10

= (13+31)/10

= 44/10

h) 2 3/5+3 2/5

= 13/5+17/5

= (13+17)/5

= 30/5

= 6

7 0

3 years ago

Evaluate the following

IRINA_888 [86]

(a) $[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

Answer:

$[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5*2.5 }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5}{1} ]^{2}$

*canceling 2.5 in numerator and denominator*

$= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925$

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) $[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3} ] ^{2}$

Answer:

$[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\$

*using $[x^{a}]^b = x^{ab}$ *

$= [\frac{3x^{3a}y^{3b}} {-3x^{3a} y^{3b} }] ^{2}$

*Again, using $[x^{a}]^b = x^{ab}$ *

$= \frac{3x^{2*3a}y^{2*3b}} {-3x^{2*3a} y^{2*3b} } \\= (-1)\frac{3x^{6a}y^{6b}} {3x^{6a} y^{6b} }\\[\tex]*taking -1 common, denominator and numerator are equal*[tex]= -(1)\frac{1}{1}\\= -1$