The age of a father is three times that of his son. In ten year's time their ages will add up to 68 years. If the son is x years old today write down an algebraic expression for: the present age of the father and the son's age in ten year's time and the father's age in 10 year's time.
1 answer:
Answer:
46 and 22
Step-by-step explanation:
let the father b (f) and d son is (s)
so
f=3s.....(1)
(f+10) +(s+10)=68 .... (2)
substitute f=3s in equation (2)
we have
(3s+10)+(s+10)=68
4s+20=68
4s=68-20
4s=48
s=12 .......(3)
substitute (3) in (1)
f=3*12
which f=36
in 10 year time
f+10 =46
s+10=22
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Step-by-step explanation :
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Step-by-step explanation:
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I the answer To You Problem Is C
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