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AleksandrR [38]
2 years ago
13

Can someone please help me with math.

Mathematics
1 answer:
Burka [1]2 years ago
8 0

Answer:

i think the answer to your question is d

Step-by-step explanation:

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Can y’all please help?
alex41 [277]

Answer:

7

Step-by-step explanation:

You subtract 220 - 129 = 91 then divide by 13

4 0
2 years ago
A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

Z_{0.95}= 1.648

1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0
2 years ago
Read 2 more answers
Write an equation in point-slope form (4,-3) (2,-9)
Tom [10]

Answer:

m = 3

Step-by-step explanation:

Try using Symbolab, I use it all the time it gives the correct answer and it gives good explanations.

8 0
2 years ago
Shade the model to 0.5 x 0.3
stellarik [79]
What model? also it would be 1/2 and 1/3
6 0
3 years ago
Read 2 more answers
Will give brainlyest if u help
goblinko [34]

Answer:

No, because it fails the vertical line test ⇒ B

Step-by-step explanation:

To check if the graph represents a function or not, use the vertical line test

<em>Vertical line test:</em> <em>Draw a vertical line to cuts the graph in different positions, </em>

  • <em>if the line cuts the graph at just </em><em>one point in all positions</em><em>, then the graph </em><em>represents a function</em>
  • <em>if the line cuts the graph at </em><em>more than one point</em><em> </em><em>in any position</em><em>, then the graph </em><em>does not represent a function </em>

In the given figure

→ Draw vertical line passes through points 2, 6, 7 to cuts the graph

∵ The vertical line at x = 2 cuts the graph at two points

∵ The vertical line at x = 6 cuts the graph at two points

∵ The vertical line at x = 7 cuts the graph at one point

→ That means the vertical line cuts the graph at more than 1 point

   in some positions

∴ The graph does not represent a function because it fails the vertical

   line test

7 0
3 years ago
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