Answer:
Number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Explanation:
Lowest four digit positive integer = 1000
Highest four digit positive integer less than 4000 = 3999
We know that multiples of 5 end with 0 or 5 in their last digit.
So, lowest four digit positive integer which is a multiple of 5 = 1000
Highest four digit positive integer less than 4000 which is a multiple of 5 = 3995.
So, the numbers goes like,
1000, 1005, 1010 .....................................................3990, 3995
These numbers are in arithmetic progression, so we have first term = 1000 and common difference = 5 and nth term(An) = 3995, we need to find n.
An = a + (n-1)d
3995 = 1000 + (n-1)x 5
(n-1) x 5 = 2995
(n-1) = 599
n = 600
So, number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Answer:
Base 5
Step-by-step explanation:
We want to determine the base at which:
113 X 2 =231
We consider the last number of the result (231).
The base must be a number such that:
3 X 2 will have a remainder of 1.
3 X 2 = 6 = 5 Remainder 1
Therefore:
113 X 2 =231 in positive integral number base 5.
Answer:noooooooooooooooooooo
Step-by-step explanation:
It would be 7:9 because if you divide each side by 4 then you can get it in simplest form
Answer:
52 degrees.
Step-by-step explanation:
