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kvasek [131]
3 years ago
8

I need help on this question ASAP.

Mathematics
2 answers:
Scrat [10]3 years ago
8 0
I’m pretty sure it’s the last answer, i checked on a graphing calculator :)
BigorU [14]3 years ago
3 0

Answer:

C

Step-by-step explanation:

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Please answer fast!!!!!
BlackZzzverrR [31]

Answer:

x = 2

Step-by-step explanation:

note that 4096 = 8^{4} , then

8^{2x} = 8^{4}

Since bases on both sides are equal, both 8 , then equate the exponents

2x = 4 ( divide both sides by 2 )

x = 2

6 0
3 years ago
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What is the answer to x+9=12
Alenkinab [10]

Answer: x = 3

Step-by-step explanation:

x + 9 = 12

x = 12 - 9

x = 3

3 0
3 years ago
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in the diagram, a building casts a 35-ft shadow and a flagpole casts a 10-ft shadow. if the flagpole is 22tall, how tall is the
8_murik_8 [283]

Let, the height of the building be x ft.

Given the building casts 35ft shadow.

The height of the flagpole given which is 22ft and casts a shadow of 10ft.

Now to find the height of the building we have to equate the ratio of height and shadow of the building and the flagpole.

So we can write,

x/35 = 22/10

To find x, we have to get rid of 35 from the left side and have to move it to right side. As 35 is divided there, we will multiply 35 to both sides.

(x/35)× 35 = (22/10)×35

x = (22×35)/10

x = 770/10

x = 77

So, the height of the building is 77 ft which is the required answer here.

8 0
3 years ago
Can someone find the surface area for this? :)
AysviL [449]

Answer:

84 :)

Step-by-step explanation:

bottom surface area= 6m^{2}

top surface area=6m^{2}

lateral surface area= 72m^{2}

add this together you get TOTAL surface area of 84

3 0
3 years ago
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Of the five quadratics listed below, four of them have two distinct roots. The fifth quadratic has a repeated root. Find the val
musickatia [10]

Answer: 3/5

Step-by-step explanation: The fourth quadratic in the list is the square of a binomial:

25x^2 - 30x + 9 = (5x - 3)^2

Therefore, the repeated root of this quadratic is the solution to 5x - 3=0, which is 3/5

6 0
3 years ago
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