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kirill [66]
2 years ago
12

12x3 + 13x – 5 2x – 1

Mathematics
1 answer:
salantis [7]2 years ago
6 0

Answer:

ANSWER: 24x^4 - 12x^3 + 26x^2 - 23x + 5

Step-by-step explanation:

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Question 1 (Multiple Choice Worth 5 points)
AysviL [449]

Answer:

Answer should be I 16-(-10) I = 26

But I guess it's the last choice you listed, I -10-16 I = 26

6 0
3 years ago
If a watch cost 40 dollars and you must pay 6.5 sales tax how much will tax be
Serhud [2]

Answer:

$100

Step-by-step explanation:

thank me later

6 0
3 years ago
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Order the steps to solve the equation log(x^2-15)=log(2x) form 1 to 5
nasty-shy [4]

Answer:x=-5 and x=3

Step-by-step explanation:

log(x^2-15)=log(2x)

Cancel log at both sides we get

x^2-15=2x

Collect like terms

x^2-2x-15=0

x^2-3x+5x-15=0

x(x-3)+5(x-3)=0

(x+5)(x-3)=0

x+5=0 x-3=0

x=-5 x=3

6 0
3 years ago
Which of the following is a factor<br> of the expression 5x^2- 13x-6?
tatiyna

Answer:

(5x+2) (x-3)

Step-by-step explanation:

4 0
2 years ago
. Using the Binomial Theorem explicitly, give the 15th term in the expansion of (-2x + 1)^19
timofeeve [1]
Let's rewrite the binomial as:
(1 - 2x)^{19}

\text{Binomial expansion:} (1 + x)^{n} = \sum_{r = 0}^n\left(\begin{array}{ccc}n\\r\end{array}\right) (x)^{r}

Using the binomial expansion, we get:
\text{Binomial expansion: } (1 - 2x)^{19} = \sum_{r = 0}^{19}\left(\begin{array}{ccc}19\\r\end{array}\right) (-2x)^{r}

For the 15th term, we want the term where r is equal to 14, because of the fact that the first term starts when r = 0. Thus, for the 15th term, we need to include the 0th or the first term of the binomial expansion.

Thus, the fifteenth term is:
\text{Binomial expansion (15th term):} \left(\begin{array}{ccc}19\\14\end{array}\right) (-2x)^{14}
3 0
3 years ago
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