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Elis [28]
3 years ago
11

Write 0.125 as a simplest fraction and percent.

Mathematics
1 answer:
DiKsa [7]3 years ago
5 0

Answer:

12½% 0.125 1/8

Step-by-step explanation:

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Find the product. (a2 + 2a + 1)(a + 1) a. A2 + 3a + 2 b. A3 + 3a2 + 3a + 1 c. A3 + 2a 2 + a + 1 d. A3 + 3a2 + a + 1
olchik [2.2K]

 (a + 1)(a² + 2a + 1)

= a(a² + 2a + 1) + 1(a² + 2a + 1)

= a³ + 2a² + a   + a² + 2a + 1

= a³ + 3a² + 3a + 1

Answer: b

7 0
3 years ago
Points A and B lie on a circle centered at point O. If what is the ratio of the area of sector AOB to the area of the circle?
Nataly [62]

Answer:

C. 1/20

Step-by-step explanation:

7 0
3 years ago
I’ll give brainliest please help asap :D
USPshnik [31]
<h3>Answer:</h3><h3> C</h3><h3 /><h3>Step-by-step explanation:</h3><h3>It is C.</h3>

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4 0
3 years ago
When two distinct circles lie in the same plane, what is the largest number of points at which they can intersect?
Rama09 [41]
All the points if they lay on top of eachother

if they arent on top of eachother, they can intersect at 2 points
6 0
3 years ago
LT1 10th grade level
Anton [14]

Answer:

The distance between the pirate and the treasure can be found from the following relationship between ΔEAF and ΔABC;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = \overline{EF}/\overline{BC}

Step-by-step explanation:

From the question diagram, we have two triangles, ΔEAF and ΔABC;

The ratio of the lengths of the sides \overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC}

∠EAF and ∠BAC are vertical angles, therefore ∠EAF = ∠BAC

Therefore, ΔEAF and ΔABC are similar triangles by Side-Angle-Side, SAS, rule of similarity which states that two triangles that have ratios of a pair of their corresponding sides and the two sides also form equal angles within each triangle, then the two triangles are similar

Therefore, the ratio of the each pair of corresponding sides of the two triangles are equal

We have;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = 50 ft. /(100 ft.) =  \overline{EF}/\overline{BC} = \overline{EF}/120 ft.

\overline{EF} = 120 ft. × 50 ft./(100 ft.) = 60 ft.

\overline{EF} = 60 ft.

The distance between the pirate and the treasure, \overline{EF} = 60 ft.

4 0
3 years ago
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