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timofeeve [1]
2 years ago
6

Help me please due in 30 minutes !

Mathematics
1 answer:
scoundrel [369]2 years ago
5 0

Answer:

B

Step-by-step explanation:

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What is the value of s in 7 = -10s - 3
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Answer:

-1 = s

Step-by-step explanation:

7 = -10s - 3

Add 3 to each side

7+3 = -10s - 3+3

10 = -10s

Divide each side by -10

10/-10 = -10s/-10

-1 = s

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Set up a proportion table, write a legend and solve the corresponding proportion. Write a sentence answering the question: Tom r
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2 years ago
Given: KLMN is a trapezoid, m∠N=m∠KML, FD=8, LM KN = 3/5 F∈ KL , D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3root5 Find: KM
Sergio039 [100]

Answer:

The length of KM is \sqrt{109} units.

Step-by-step explanation:

Given the statement:  KLMN is a trapezoid, ∠N= ∠KML, FD=8, \frac{LM}{KN}=\frac{3}{5}, F∈ KL, D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3\sqrt{5}.

From the given information it is noticed that the point F and D are midpoints of KL and MN respectively.

The height of the trapezoid is 3\sqrt{5}.


Midsegment is a line segment which connects the midpoints of not parallel sides. The length of midsegment of average of parallel lines.


Since \frac{LM}{KN}=\frac{3}{5}, therefore LM is 3x and KN is 5x.

\frac{3x+5x}{2}=8

\frac{8x}{2}=8

x=2

Therefore the length of LM is 6 and length of KN is 10.

Draw perpendicular on KN form L and M.

KN=KA+AE+EN

10=6+2(EN)                (KA=EN, isosceles trapezoid)  EN=2

KE=KN-EN=10-2=8

Therefore the length of KE is 8.

Use Pythagoras theorem is triangle EKM.

Hypotenuse^2=base^2+perpendicular^2

(KM)^2=(KE)^2+(ME)^2

(KM)^2=(8)^2+(3\sqrt{5})^2

KM^2=64+9(5)

KM=\sqrt{109}

Therefore the length of KM is \sqrt{109} units.

6 0
3 years ago
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