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nataly862011 [7]
2 years ago
15

Find the mssing value. I = ? , P = $250.00, r = 4%, t = 2 years

Mathematics
1 answer:
Ber [7]2 years ago
4 0

Answer:

20 I think

Step-by-step explanation:

I mean I would say it is 20

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yaroslaw [1]
1,234

One thousand
Two hundred
Thirty four
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Is 12.56 greater than or less than 125.6
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12.56 is less than 125.6 which could also be written as 12.56<125.6. 12.56 comes farther left on the number line and is of lesser value when compared to the number 125.6.
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Reflection Over Parallel Lines Please complete the attached reflection. Thanks!
Allushta [10]

Answer: A(3, -5)

B(6, -2)

C(9, -2)

Step-by-step explanation:

If we have a point (x, y), and we do a reflection over the axis y = a, then the only thing that will change in our point is the value of x.

Now, the distance between x and a must remain constant before and after the reflection.

so if x - a = d

then the new position of the point will be:

(a - d, y) = (2a - x, y).

I will use that relationship for the 3 points

A)

We start with the point (1, -5)

The reflection over y = -1 leaves.

The distance between 1 and -1 is = 1 - (-1) = 2.

Then the new point is (-1 - 2, -5) = (-3, -5)

Now we do a reflection over y = 1, so D = -3 - 1 = -2

Then the new point is:

A = (1 -(-2), -5) = (3, -5)

B) (2, -2)

Reflection over y = -1.

distance, d = 2 - (-1) = 3

the point is (-1 - 3, -2) = (-4, -2)

Now, a reflection over y = 1.

The distance is D = -4 - 1 = -5

The new point is (1 - (-5), 2) = (6, -2)

C) (5, -2)

reflection over y = -1

Distance: D = 5 - ( - 1) = 6

New point: (-1 - 6, -2) = (-7, -2)

Reflection over y = 1.

Distance D = -7 - 1 = -8

New point ( 1 - (-8), -2) = (9, -2)

4 0
3 years ago
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
miss Akunina [59]

Answer:

a. 0.343

b. 0.657

c. 0.189

d. 0.216

e. 0.353

Step-by-step explanation:

We use the combination formula of probability distribution to solve the question.

Where P(x=r) = nCr * p^r * q^n-r

Where n = number of trials = 3 vehicles

r = desired outcome of trial which varies.

p = probability of success = 70% =0.7

q = probability of failure = 1-p = 0.3

a. Probability that all 3 vehicles passed = P(X=3)

= 3C3 * 0.7^3 * 0.3^0 = 1 * 0.343 * 1

= 0.343.

b. Probability that at least one fails = 1 - (probability that none failed)

And probability that none failed = probability that all 3 vehicles passed.

Hence Probability that at least one fails = 1 - (probability that all 3 vehicles passe)

= 1 - 0.343

= 0.657

c.) probability that exactly one pass= P(X=1)

= 3C1 * 0.7¹ * 0.3² = 3 * 0.7 * 0.09

= 0.189

d.) probability that at most One of the vehicles passed = probability that none passed + probability of one passed.

Probability that none of the vehicles passed = P(X=0)

= 3C0 * 0.7^0 * 0.3^3 = 1*1*0.027

=0.027

Probability that one passed as calculated earlier = 0.189

Hence probability that at most one vehicle passed = 0.189 + 0.027 = 0.216

e.) Probability that all three Vehicles pass given that at least one pass = (probability of all three vehicles passes) / (probability that at least one passes)

Probability that at least one pass = 1 - probability that none passed.

= 1 - 0.027

= 0.973

Hence,

Probability that all three Vehicles passed given that at least one passed = 0.343/0.973

= 0.3525 = 0.353 (3.d.p)

7 0
3 years ago
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