Y = y0 + V0y * t + gt^2 / 2
y0 = 0
g ≈ - 32 ft / s^2
(1) y = V0y * t - 16t^2
(2) x = V0x * t
Use (1) and the maximum heigth formula to determine V0y
y max = (V0y)^2 / (2g) = 200 => (V0y)^2 = 2*32*200 = 12,800 => V0y ≈ 113.14 ft/s
y = 113.14 t - 16t^2
for y = 200 => 200 = 113t - 16t^2 => -16t^2 + 113.14t - 200 = 0
Solve that equation using the quadratic formula and you will ge t = 3.54 s
The total time is 3.54 s * 2 = 7.08 s
Then use that time in (2) to find V0x
600 = V0x * t => V0x = 600 / 7.08 s = V0x = 84.7 ft/s
Then, x = 84.7 t.
Now solve for t and replace it in y = 113.14 t - 16t^2 :
t = x / 84.7
y = 113.14 (x/84.7) - 16(x^2 / 84.7 ^2) = 1.336 x - 0.00223x^2
You can check that for, except for a small difference due to the approximations, for x = 600, y = 0 and for x =300 y = 200
Answer: y = 1.336 x - 0.00223x^2
The area is the product of the dimensions (length x width).
If the dimensions must be whole numbers and the area is 42 square feet,
then the dimensions can only be . . .
1-ft by 42-ft
2-ft by 21-ft
3-ft by 14-ft
or
6-ft by 7-ft .
6-ft by 7-ft probably makes the most sense for a quilt.
Answer:
............................................................ esssssupido
Answer: The height of the tree will be 21 meters
