Please help divide 10u^2− 4u/2u

So what is the answer?

Dimas [21]

Answer for what?????

4 0

3 years ago

V square+6v-59=0 answer in one equation

Tema [17]

X= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$
a=1
b=6
c=-59
x= $\frac{-6+/- \sqrt{(6)-4(1)(-59)} }{2(1)}$
x= $-3+ 2\sqrt{17}$ and $-3- 2\sqrt{17}$

8 0

3 years ago

Anthony borrowed $18,800 at 6% simple interest for 4 months. Determine the amount of interest.

anygoal [31]

First, converting R percent to r a decimal
r = R/100 = 6%/100 = 0.06 per year,
putting time into years for simplicity,
4 months ÷ 12 months/year = 0.333333 years,
then, solving our equation

I = $ 376.00

I = 18800 × 0.06 × 0.333333 = 375.999624
I = $ 376.00

The simple interest accumulated
on a principal of $ 18,800.00
at a rate of 6% per year
for 0.333333 years (4 months) is $ 376.00.

5 0

3 years ago

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes

$\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}$

hence the answer is 0.4823

(iii) All are defective

$\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}$

(iv) At least one is defective

This is 1 - probability that none is defective

$\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}$

Hence the answer is 0.5177

3 0

1 year ago

Lunch break: In a recent survey of 655 working Americans ages 25-34, the average weekly amount spent on lunch was $43.5

Inga [223]

Using the Empirical Rule, it is found that:

a) Approximately 99.7% of the amounts are between $35.26 and $51.88.
b) Approximately 95% of the amounts are between $38.03 and $49.11.
c) Approximately 68% of the amounts fall between $40.73 and $46.27.

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The Empirical Rule states that, in a bell-shaped distribution:

Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.

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Item a:

$43.5 - 3(2.77) = 35.26$