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Rashid [163]
3 years ago
14

Sketch a graph of the function. y= 3(x-4)^2-4

Mathematics
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

9√6π6÷3-7

Step-by-step explanation:

because I dont know lol

I have written the wrong answer

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37.50 divide by 5.25 and the answer is 7
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Triangle A B C is reflected and then dilated to form smaller triangle A double-prime B double-prime C double-prime Which transfo
Gnoma [55]

Answer:

a reflection and a dilation

Step-by-step explanation:

in the wording, it was stated that the triangle was reflected then dilated.

6 0
4 years ago
What is an equation of the line that passes through the points (0,-5) and (-6,0)?
charle [14.2K]

Answer:

y=-5/6x-5

Step-by-step explanation:

0-(-5)/-6-0

-5/6 slope

y-(-5)=-5/6(x-0)

y+5=-5/6x

y=-5/6x-5

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Are AB and CD parallel, perpendicular, or neither?*<br> 1. A(-4, 8), B(4, 10), C(1, 1), D(-2, 13)
ohaa [14]

Answer:

Perpendicular

<em />

Step-by-step explanation:

Given

A = (-4, 8)

B = (4, 10)

C = (1, 1)

D = (-2, 13)

Required

Is AB and CD parallel?

First, we need to calculate the slope (m) of AB and CD

m = \frac{y_2 - y_1}{x_2 - x_1}

For AB:

A (x_1,y_1)= (-4, 8)

B(x_2,y_2) = (4, 10)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{10 - 8}{4 - (-4)}

m = \frac{10 - 8}{4 +4}

m = \frac{2}{8}

m = \frac{1}{4}

For CD:

C(x_1,y_1) = (1, 1)

D(x_2,y_2) = (-2, 13)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{13 - 1}{-2 - 1}

m = \frac{12}{-3}

m = -4

For Lines to be parallel, the slope must be equal:

i.e. m_1 = m_2

This condition is not true because:

\frac{1}{4} \neq -4

For Lines to be perpendicular, the slope must be:

m_1 = -\frac{1}{m_2}

This implies:

\frac{1}{4} = -\frac{1}{-4}

\frac{1}{4} = \frac{-1}{-4}

\frac{1}{4} = \frac{1}{4}

<em>Hence, the lines are perpendicular</em>

6 0
3 years ago
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