Insert 2 rational numbers between -1/3 and -1/2

Mathematics

1 answer:

Natalka [10]3 years ago

7 0

Answer:

-11/24 and -4/9

Step-by-step explanation:

A rational number is a fraction in the form a/b where both a and b are integers and b is not equal to zero.

Given the numbers -1/3 and -1/2, to place two numbers between them, we have to first find the width between the two numbers.

Width = -1/3 - (-1/2) = -1/3 + 1/2 = 1/2 - 1/3 = 1/6

Since two numbers are to be placed between -1/3 and -1/2, we have to divide the width into 3 which results to 1/6 ÷ 3 = 1/18

The first number placed is -1/3 - 1/18 = -11/24

The second number is -11/24 - 1/18 = -4/9

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denis23 [38]

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Check below

Step-by-step explanation:

Hi,

We're dealing with linear functions. $f(x)=mx+b$

We have here the first function.

$g(x)=3x$

That's a linear function, with slope, and no linear coefficient since

But on the other hand, the functions below, they all describe parallel lines, since their slope has the same value. I've changed the letters to make it easier the comprehension.

Even though each one has the same slope value, they have different non zero linear coefficients, {-6,-18,6,18}. Unlike, the first one

$h(x)=3(9x-2) \rightarrow h(x)= 27x-6\\i(x)=9(3x-2)\rightarrow i(x)=27x-18\\j(x)=3(9x+2)\rightarrow j(x)=27x+6 \\k(x)=9(3x+2)\rightarrow k(x)=27x+18\\$