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Katyanochek1 [597]
3 years ago
9

A golf ball is hit from ground level. Its path is modelled by the relation h(t) = -4.9 t2 + 27.2t , where h is the ball’s height

above the ground, in meters, and t is the time, in seconds. Determine the time the ball is in the air.
Mathematics
1 answer:
tigry1 [53]3 years ago
8 0
Well its in the air any time marked on the parabola but assuming that time is the difference between the two x intercepts it would be 5.551 seconds. (Sorry im not 100 percent sure what it means)
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Multiply.
vodomira [7]

028282=099÷00÷00÷0÷=0÷9282=

6 0
4 years ago
Plz help I'll give brainlest
jarptica [38.1K]
<h3>1.Area of the parallelogram= 288 square units</h3><h3>2.Area of the parallelogram=45 m^2</h3><h3>3.Area of the trapezoid   = 34 square in.</h3><h3>4.Area of the trapezoid = 8 square ft</h3><h3>5.Area of the rhombus= 27 square cm</h3><h3>6.Area of the rhombus= 108 square in</h3><h3>7.The area of the desktop is  = 1200 square in</h3><h3>8.The area of the rhombus is =84 cm^2</h3><h3>9.Area of the trapezoid  = 240 square ft</h3>

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

                                       =16× 18 square units

                                       = 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

                                        =(9×5) m^2

                                         =45 m^2

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the  trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                            =\frac{1}{2} \times (12+5) \times 4 square in.

                             = 34 square in.

4.

Height = 2 ft  and parallel sides are 2 ft and 6 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                              =\frac{1}{2} \times (2+6) \times 2 square ft

                              = 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 6\times 9 square cm

                               = 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 12\times 18 square in

                               = 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

                                            = 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = \frac {1}{2} \times 14 \times 12 cm^2

                                         =84 cm^2

9.Given , the base of trapezoid are 24 ft  and 16 ft and height is 12 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                                    = \frac{1}{2} \times (24+16) \times 12 square ft

                                     = 240 square ft

8 0
3 years ago
at Alan's sports shop, GO FAST trainers cost £40.95 originally and there is a third off in the sale.  At  Irene's sport shop, GO
dem82 [27]
The trainers will be cheaper at Alan's sport shop.

prices ->
Alan's: 27.30
Irene's: 28.00

\frac{1}{3} of 40.95 can be calculated as follows ->

\frac{1}{3} = \frac{x}{40.95}
simplify to get that x = 27.30

30% of 40.00 can be calculated as follows ->

\frac{30}{100} = \frac{x}{40.00}
simplify to get that x = 28
7 0
4 years ago
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tankabanditka [31]

Answer:

(3+2)×5= 5 power 2

5 power 3= 125

10 power 2 over 2= 50

Step-by-step explanation:

6 0
3 years ago
How to use Pythagorean theorem to find the right triangle side length
MrRissso [65]

Answer:

You would use a^2 + b^2 = c^2

Step-by-step explanation:

a and b are the shorter side of the triangle whereas c is the hypotenuse or longest side of the triangle

5 0
4 years ago
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