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zepelin [54]
3 years ago
6

PLEASE HELP EXPLAIN THIS!!!!!

Mathematics
2 answers:
Neko [114]3 years ago
7 0

Answer:

Step-by-step explanation:

Look at the number and the angles

Multiple the angles all together that's how u find x

nlexa [21]3 years ago
3 0

Answer:

The answer for number one is X=37. This is because 37 is half of 74.

Basically, these are all equal angles. The ones across from eachother are, and the angles that are right next to eachother are always going to equal 180, or half of 360. Number 4 is the same as the rest, but it seems more confusing because of the 5th line. If you add 55 and 85, then divide it by 8, you will get the answer.

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My assigned ratio is: 2:5 Give Two examples of ratios that are equivalent to my ratio:
horrorfan [7]

Answer:

4:10 and 6:15 are equivalent to 2:5

5 0
3 years ago
Given a line segment with endpoints A(16, 8) and B(1, 3) what are the coordinates of the
blondinia [14]

Answer:

The line segment partitioned two-fifths from A to B is (10,6)

Step-by-step explanation:

First point from A to B is (16,8)

than find the difference between A to B i.e B - A

(1,3)-(16,8) = (-15,-5)

To measure the (2/5) difference we will multiply (-15,-5) with  (2/5) which is equal to (-6,-2)

Now Add the difference to the first coordinate (point A) gives

Point of division = (16,8)+(-6,-2)

Point of division = (16-6, 8-2)

Point of division = (10,6)

4 0
3 years ago
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m_a_m_a [10]

Answer:o

Step-by-step explanation:

5 0
3 years ago
Find the real solutions of the equation by graphing. x^2 + 2x + 2 = 0
Furkat [3]
<span>for example, (1;5)
-----------------------------</span>

8 0
3 years ago
Read 2 more answers
There is a photo attached
natulia [17]

You can use the sum of angles identities, then rearrange to put the result in the form of tangents.

\displaystyle\frac{\sin{(x+y)}}{\sin{(x-y)}}=\frac{\sin{(x)}\cos{(y)}+\cos{(x)}\sin{(y)}}{\sin{(x)}\cos{(y)}-\cos{(x)}\sin{(y)}}\\\\=\frac{\left(\frac{\sin{(x)}\cos{(y)}+\cos{(x)}\sin{(y)}}{\cos{(x)}\cos{(y)}}\right)}{\left(\frac{\sin{(x)}\cos{(y)}-\cos{(x)}\sin{(y)}}{\cos{(x)}\cos{(y)}}\right)}\\\\=\frac{\tan{(x)}+\tan{(y)}}{\tan{(x)}-\tan{(y)}}

6 0
3 years ago
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