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Elden [556K]
3 years ago
15

12 PTS; IF IT'S RIGHT I Promise BRAINLIST;5-STARS;THANKS; Beleive me it's simple I promise!!

Mathematics
2 answers:
NARA [144]3 years ago
8 0

Not to be a stalker but I have this same test it’s

Functions Unit Review

answers
1. C
2. B
3. D
4. D
5. D
6. D
7. B

vlabodo [156]3 years ago
4 0

Answer:

1. C

2. I'm not sure but i think its neither

3. C

4. D

Notify me if any of them are wrong, and please tell me which was the correct answer :)

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Is N² + N always an even number? Explain
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Answer:

Yes

Step-by-step explanation:

Yes.

Let's first start with even numbers. (N - even number)

Any even number squared, is an even number. Then, we add that squared even number to another even number which would give us an even number.

Now, let's see odd numbers.

Any odd number squared would be an odd number. When you add "N", it would be adding an odd number to an odd number, which gives you an even number.

OR

We can start by factoring the expression:

N^2+N=N(N+1)

This is essentially multiplying two consecutive numbers, which in turn means that one number has to be even, and one has to be odd. An odd number multiplied by an even number will always be even.

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3 years ago
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3 years ago
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If the length of the longest side of a right triangle is 10 inches is 60 degrees, what is the length (in inches) of the shortest
Scorpion4ik [409]
Yep 5 is correct! Good job
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The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

7 0
3 years ago
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