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3 years ago

NEED HELP ASAP FIND the missing side of the triangle

Mathematics

1 answer:

Marina86 [1]3 years ago

6 0

Answer:

Step-by-step explanation:

using Pythagoras theorem:

29²-21²= 400

√400 = 20

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Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=

Ganezh [65]

Answer:

$y(1+x)+x-5\ln xy=C$

Step-by-step explanation:

Consider the given differential equation is

$(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1$

$(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y$

$(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx$

Taking all variables on right sides.

$(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0$

$(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0$

Let as assume,

$M=-\frac{5}{x}+1+y$ and $N=1-\frac{5}{y}+x$

Find partial derivatives $\frac{\partial M}{\partial y}$ and $\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$ and $\frac{\partial N}{\partial x}=1$

Since $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ , therefore the given differential equation is exact.

The solution of the exact differential equation is

$\int Mdx+\int N(\text{without x)}dy=C$

$\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C$

$yx-5\ln x+x+y-5\ln y=C$

$y+x+xy-5\ln x-5\ln y=C$

$y(1+x)+x-5(\ln x+\ln y)=C$

$y(1+x)+x-5\ln xy=C$

7 0

3 years ago

Honda Atlas issued 100,000 shares of stock. In 1990, each share of stock was worth Rs. 152.50. In 1993, each share of the stock

noname [10]

Answer:

Rs.13,130 ,000

Step-by-step explanation:

Lets solve first for year 1990

Value of stock in 1990 = Rs. 152.50

No. of stocks issued in 1990 = 100,000

Total value of these stocks in 1990= Value of stock in 1990* no of stocks issued in 1990 = 152.50*100,000 = Rs. 15,250,000

Let solve first for year 1993

Value of stock in 1993 = Rs. 21.20

No. of stocks 1993 = 100,000

Total value of these stocks in 1993 = Value of stock in 1993* no of stocks issued in 1993 = 21.20*100,000 = Rs. 2,120,000

Decrease in value of stock in 1993 in comparison to 1990 = Total value of the stocks in 1990 -Total value of the stocks in 1993

= Rs. 15,250,000 - Rs. 2,120,000

= Rs.13,130 ,000

Thus, the 100,000 shares worth Rs.13,130 ,000 lesser in 1993 than in 1990.

6 0

3 years ago

How can you check to see if two fractions are equivalent please explain

Wewaii [24]

Answer:

cross multiply and they should equal the same

Step-by-step explanation:

4 0

3 years ago

Chad has $420 to invest. The price of a stock is $6.82 per share. What is the greatest number of whole shares Chad can buy?

gregori [183]

Approximately 61.

if you divide 420 by 6.82 you get 61.58 :)

3 0

3 years ago

What fraction is equal to 65%?

umka21 [38]

Answer:

65/100

Divide is by 100.

4 0

3 years ago