Organic chemistry is all about CARBON!!!!!!
<span>Chemical reaction: CH</span>₃COO⁻(aq) + H⁺(aq) ⇄ CH₃COOH(aq).
H⁺ is from HNO₃: HNO₃ → H⁺ + NO₃⁻.
<span>A buffer can
be defined as a substance that prevents the pH of a solution from changing by
either releasing or absorbing H</span>⁺ in a
solution.
Buffer is a solution
that can resist pH change upon the addition of an acidic or basic components
and it is able to neutralize small amounts of added acid or base, pH of
the solution is relatively stable.
The notion <span>an empty balloon have precisely the same apparent weight on a scale as a balloon filled with air depends on the diameter of the balloon. The weight of the balloon filled with air is equal to the mass of the balloon and the mass of the air inside. The mass of air inside is equal to the density of air multiplied by the volume of the balloon. If the balloon is large, then the two masses are equal whereas if not, the mass of air inside the inflation is neglible</span>
Answer:
The answer is C, both krypton and neon.
Explanation:
I got the answer wrong and my teacher told me that c is the right answer choice
Answer :
(A) The number of moles of 
ions per liter is, 0.1 moles/L
(B) The number of molecules of 
ion is, 
(C) The pH of the solution will be, 4
<u>Solution for part A :</u>
First we have to calculate the pOH of the solution.
As we know that,
Now we have to calculate the moles of ion per liter.
![pOH=-\log [OH^-]\\\\1=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D%5C%5C%5C%5C1%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=0.1moles/L](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D0.1moles%2FL)
<u>Solution for part B :</u>
First we have to calculate the ion concentration.
![pH=-\log [H^+]\\\\13=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D%5C%5C%5C%5C13%3D-%5Clog%20%5BH%5E%2B%5D)
![[H^+]=10^{-13}moles/L](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-13%7Dmoles%2FL)
Now we have to calculate the number of molecules of ion
As, 1 mole contains 
number of molecules of ion
So, 
moles contains 
number of molecules of ion
<u>Solution for part C :</u>
![pH=-\log [H^+]\\\\pH=-\log (1\times 10^{-4})](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D%5C%5C%5C%5CpH%3D-%5Clog%20%281%5Ctimes%2010%5E%7B-4%7D%29)
