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mixas84 [53]
3 years ago
8

Which acid is the acid usually found in your stomach?

Chemistry
1 answer:
amid [387]3 years ago
4 0

Answer:

A.hydrochloric acid

Explanation:

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Choose the molecular compound among the substances listed below.
agasfer [191]

Answer: Among the listed substances XeCl_{4} is the molecular compound.

Explanation:

A chemical compound formed by the chemical combination of two or more non-metals is called a molecular compound or covalent compound.

For example, Xe and Cl are non-metals. The compound formed by them is XeCl_{4} which is a molecular compound.

A molecular compound is formed by sharing of atoms between the combining atoms.

Whereas NaF, MnCl_{2} and CaO are all ionic compounds as they are formed by chemical combination of a metal and a non-metal.

Thus, we can conclude that among the listed substances XeCl_{4} is the molecular compound.

4 0
3 years ago
The solubility of nitrogen gas at 25 degrees C and 1 atm is 6.8 x 10^(-4) mol/L. If the partial pressure of nitrogen gas in air
Zolol [24]

Answer:

5.2 x 10⁻⁴ M.

Explanation:

  • The relationship between gas pressure and the  concentration of dissolved gas is given by  Henry’s law:

<em>P = kC</em>

where P is the partial pressure of the gaseous  solute above the solution.

k is a constant (Henry’s constant).

C is the concentration of the dissolved gas.

  • At two different pressures, there is two different concentrations of dissolved gases and is expressed in a relation as:

<em>P₁C₂ = P₂C₁,</em>

P₁ = 1.0 atm, C₁ = 6.8 x 10⁻⁴ mol/L.

P₂ = 0.76 atm, C₂ = ??? mol/L.

<em>∴ C₂ = (P₂C₁)/P₁ =</em> (0.76 atm)(6.8 x 10⁻⁴ mol/L)/(1.0 atm) = <em>5.168 x 10⁻⁴ mol/L ≅ 5.2 x 10⁻⁴ M.</em>

5 0
3 years ago
Standard reduction potentials for nickel(II) and copper(II) The standard reduction potential for a substance indicates how readi
AleksandrR [38]

Answer:

The standard potential, E cell, for this galvanic cell is 0.5670V

Explanation:

Ni²⁺(aq)  +  2e⁻   →   Ni(s)           E red =  - 0.23V      ANODE

Cu²⁺(aq) +  2e-    →  Cu(s)          E red = + 0.337V    CATHODE

ΔE° = E cathode - E anode

ΔE° = 0.337V - (0.23V) = 0.5670 V

6 0
3 years ago
How many moles of aluminum oxide will be produced from 0.50 mol of oxygen? 4 al + 3 o2 2 al2o3?
LuckyWell [14K]
From the equation;
 4 Al + 3 O2 = 2 Al2O3
The mole ratio of Oxygen is to Aluminium hydroxide is  3:2.
Therefore; moles of Al2O3 is 
 (0.5/3 )× 2 = 0.333 moles
Therefore; The moles of aluminium oxide will be 0.333 moles
5 0
3 years ago
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3 years ago
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