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patriot [66]
2 years ago
10

Lien made this table to organize her notes on the properties of acids and bases. Which property is in the wrong column? conduct

electric current taste bitter feel slippery react with lipids
Chemistry
2 answers:
OLEGan [10]2 years ago
8 0
Tatses bitter is the anwser i did the test
nalin [4]2 years ago
6 0

Answer is: taste bitter.

1) acids taste sour, bases taste bitter.

2) Acids and bases give ions in water solutions, so they conduct electricity.

3) bases have pH greater than 7, acids have pH less than 7.

4) red litmus turn blue whe base is drop on it and blue litmus turn red when acid is drop on it.

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zheka24 [161]

Answer:

It is less dense. It is also less dense than the oceanic crust.

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2 years ago
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3 0
2 years ago
The reaction nacl(s) → nacl(aq) is performed in a coffee cup calorimeter, using 100 ml of h2o(l) and 5.00g of nacl. if the tempe
MrRissso [65]

Since the density of water is 1 g /mL, hence there is 100 g of H2O. So total mass is:

m = 100 g + 5 g = 105 g

 

=> The heat of reaction can be calculated using the formula:

δhrxn = m C ΔT

where m is mass, C is heap capacity and ΔT is change in temperature = negative since there is a decrease

 

δhrxn = 105 g * 4.18 J/g°C * (-2.30°C)

δhrxn = -1,009.47 J

 

=> However this is still in units of J, so calculate the number of moles of NaCl.

 

moles NaCl = 5 g / (58.44 g / mol)

moles NaCl = 0.0856 mol

 

=> So the heat of reaction per mole is:

δhrxn = -1,009.47 J / 0.0856 mol

δhrxn = -11,798.69 J/mol = -11.8 kJ/mol

5 0
3 years ago
The amount of matter in an object is considered to be its _____. size volume area mass density
marta [7]
The amount of matter in an object is consisted to be MASS .
6 0
2 years ago
Given the following information:Br2 bond energy = 193 kJ/mol F2 bond energy = 154 kJ/mol 1/2Br2(g) + 3/2F2(g) -> BrF3(g) = –3
arlik [135]

Answer:

C) 712 KJ/mol

Explanation:

  • ΔH°r = Σ Eb broken - Σ Eb formed
  • 1/2Br2(g) + 3/2F2(g) → BrF3(g)

∴ ΔH°r = - 384 KJ/mol

∴ Br2 Eb = 193 KJ/mol

∴ F2 Eb = 154 KJ/mol

⇒ Σ Eb broken = (1/2)(Br-Br) + (3/2)(F-F)

⇒ Σ Eb broken =  (1/2)(193 KJ/mol) + (3/2)(154 KJ/mol) = 327.5 KJ/mol

∴ Eb formed: Br-F

⇒ Σ Eb formed (Br-F) = Σ Eb broken - ΔH°r

⇒ Eb (Br-F) = 327.5 KJ/mol - ( - 384 KJ/mol )

⇒ Eb Br-F = 327.5 KJ/mol + 384 KJ/mol = 711.5 KJ/mol ≅ 712 KJ/mol

8 0
3 years ago
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