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3 years ago

HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

posledela3 years ago

5 0

Answer:

The ballet dancers practice 20 h or more per week. is right

The jazz dancers practice 20 h or more per week. is wrong

The type of dancing does not seem to affect the number of hours of practice for the dancers in the survey. is right

Step-by-step explanation:

i took the test so no step by step :)

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Write an equation parallel to y=3x−1 y=3x−1 and goes through the point (-2, -13)

Lena [83]

Answer:

y=3x-(-2,-13)

Step-by-step explanation:

3 0

2 years ago

I NEED HELP NOW!!! I ONLY HAVE 5 MIN TO TURN THIS IN

zubka84 [21]

Answer:

28000 + 3000·x = 36000 + 2000·x --> x = 8 years

28000 + 3000·8 = $52000

4 0

3 years ago

Read 2 more answers

Need help please don't know this no links

abruzzese [7]

Answer:

$551

Step-by-step explanation:

The maximum profit is found where the derivative of the profit function is 0.

y' = -2x +62 = 0

x = 62/2 = 31

Then the maximum profit is ...

y = (-x +62)x -410

y = (-31 +62)(31) -410 = 961 -410 = 551

Assuming the profit is in dollars, the maximum profit the company can make is 551 dollars.

4 0

2 years ago

Use the distributive property to create an equivalent expression.<br><br> 7(8j + 4 + 9j)

Scorpion4ik [409]

Answer:

119j+28

Step-by-step explanation:

7(17j+4) Remove the parentheis

distribute 7 through the parentheis

4 0

2 years ago

PLEASE PLEASE ANSWER!

muminat

The area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = $\frac{1}{2}\times \pi r^2$

$$=\frac{1}{2}\times \pi\times 4^2$

$$=\frac{1}{2}\times \pi\times 16$

Area of the semi-circle = $$8\pi$ cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

$AC^2+BC^2=AB^2$

$AC^2+4^2=8^2$

$AC^2=64-16$

$AC^2=48$

$AC=4\sqrt{3}$ cm

Base of the triangle ABC = $4\sqrt{3}$ cm

Height of the triangle = 4 cm

Area of the triangle ABC = $\frac{1}{2}\times b \times h$

$$=\frac{1}{2}\times 4\sqrt{3} \times 4$

Area of the triangle ABC = $8\sqrt{3}$ cm²

Area of the shaded region

= Area of the semi-circle – Area of the triangle ABC

= $$8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2$

= $$8(\pi \ -\sqrt{3})\ \text{cm}^2$

Hence the area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

3 0

2 years ago