Answer:
(M)_a = -8171 lb-ft
Step-by-step explanation:
Step 1:
- We will first mark each weight from left most to right most.
Point: Weight: Moment arm r_a
G_3 W_g3 = 169 30*Cos(75) + 4.25
G_2 W_g2 = 220 30*Cos(75) + 2.5
G_1 W_g1 = 1500 10*cos(75)
Step 2:
- Set up a sum of moments about pivot point A, the expression would be as follows:
(M)_a = -W_g3*(30cos(75) + 4.25) - W_g2*(30*Cos(75) + 2.5) - W_g1*10*cos(75)
Step 3:
- Plug in the values and solve for (M)_b, as follows:
(M)_a = -169*(30cos(75) + 4.25) - 220*(30*Cos(75) + 2.5) - 1500*10*cos(75)
(M)_a = -2030.462559 -2258.205698 - 3882.285677
(M)_a = -8171 lb-ft
Answer:
The maximum value of C is 68
Step-by-step explanation:
we have the following constraints
----> constraint A
----> constraint B
----> constraint C
----> constraint D
Find out the area of the feasible region, using a graphing tool
The vertices of the feasible region are
(0,0),(5,19),(5,0)
see the attached figure
To find out the maximum value of the objective function C, substitute the value of x and the value of y of each vertex in the objective function and then compare the results
For (0,0) -----> 
For (5,19) -----> 
For (5,0) -----> 
therefore
The maximum value of C is 68
The answer is C i know for a fact
Answer:
False
Step-by-step explanation:
The equation is equal to -24 = -19. That's not true
The answer I believe is 5.8
