Do the exponents first. 10 to the -4 is 1/10000 or 0.0001 and 10^ -5 is 0.00001. You end up with (1.7*0.0001)(5*0.00001) which is 0.00017*0.00005 which is 0.0000000085 or 0.085*10^-8

5 0

3 years ago

Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a

andrew11 [14]

Answer:

Step-by-step explanation:

Given that the number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter μ = 20 (suggested in the article "Dynamic Ride Sharing: Theory and Practice"†).

a) $P(X\leq 15) = 0.1565=0.157$

b) $P(X>26) =1-F(26)\\= 1-0.9221\\=0.0779=0.078$

c) $P(15\leq x\leq 26)\\=F(26)-F(14)\\=0.9221-0.1049\\=0.8172=0.817$

d) 2 std dev = 2(20) =40

Hence 2 std deviation means

20-40, 20+40

i.e. (0,60)

$P(0$

5 0

3 years ago