In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.
Let's start with the first equation.
Cross multiply both sides of the equation.
Subtract 6x on both sides of the equation.
Divide both sides of the equation by -5.
Therefore, the slope of the first equation is 4/5.
Let's now simplify the second equation.
Add x on both sides of the equation.
Divide both sides of the equation by -4.
Therefore, the slope of the second equation is -5/4.
Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.
Answer:
B. Use the coordinate pairs to show that an equation of the form y = x + c can be written. C. List out the coordinate pairs and show that each y–value is a multiple of its associated x–value. D. Plot the coordinate pairs on a graph and show that the points make a straight line through the origin.
Step-by-step explanation:
Answer:
umm what
Step-by-step explanation:
Answer:
11 units
Step-by-step explanation:
Just trust me!
Answer:
1. x = ±9
2. 
3. 12 and -12.
4. Antoine is incorrect. There exists two solutions x=5 and x= -5.
Step-by-step explanation:
According to the questions,
Problem 1. 
i.e. 
i.e. x = ±9.
Problem 2. 
i.e. 
i.e. 
i.e.
Problem 3. [tex]f(x)=x^{2}-144[tex]
To find the roots, we take, [tex]x^{2}-144=0[tex] i.e. [tex]x^{2}=144[tex] i.e. x = ±12.
Thus, the options are 12 and -12.
Problem 4. We have [tex]f(x)=x^{2}+25[tex]
For the roots, we take, [tex]x^{2}+25=0[tex] i.e. [tex]x^{2}=25[tex] i.e. x = ±5.
Thus, Antoine is not correct and two solutions namely x=5 and x= -5 exists.
