Answer:
x=pi/3 + 2pi*k
x=2pi/3+2pi*k
Step-by-step explanation:
sin(x)=sqrt(3)/2
This happens twice in the first rotation on our unit circle.
It happens in the first quadrant and in the second quadrant. Third and fourth quadrants are negative for sine.
So we are looking for when the y-coordinate on the unit circle is sqrt(3)/2.
This is at pi/3 and 2pi/3.
So we can get all the solutions by adding +2pi*k to both of those. This gives us a full rotation about the circle any number of k times. k is an integer.
So the solutions are
x=pi/3 + 2pi*k
x=2pi/3+2pi*k
Answer:
infinite solutions
Distributive Property
Step-by-step explanation:
5x + 3(x − 5) = 6x + 2x − 15
Distribute
5x+3x -15 = 6x+2x -15
Combine like terms
8x -15 = 8x-15
Subtract 8x from each side
8x-8x-15 = 8x-8x-15
-15=-15
This is always true so there are infinite solutions
We used the Distributive Property
And the Subtraction Property of Equality
Answer: 2x^3 - 6x^2 - 14x + 24
