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3 years ago

What is Ten percent of a number added to that number?

1 answer:

8 0

Let x be this number 10% of the number x is (10%)(x) → 0.1x
Then 10% of a number x, added to that number is (1.1x):

x + 0.1x = x(1+0.1) = x(1.1) = 1.1x

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URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

3 years ago

Help please ASAP please I’ll mark you as brainlister

storchak [24]

Answer:

a = 4

Step-by-step explanation:

$\sin(theta) = \frac{opposite}{hypotenuse}$

$\cos(theta) = \frac{adjacent}{hypotenuse}$

$\tan(theta) = \frac{opposite}{adjacent}$

hypotenuse = a

opposite = 2√3

adjacent = b

theta = 60°

the best formula to use is the first formula cause we have all the values to substitute in it in order to find the value of a

$\sin(60) = \frac{2 \sqrt{3} }{a}$

$\frac{2 \sqrt{3} }{ \sin(60) } = a$

$4 = a$

$a = 4$

4 0

3 years ago

Whats the simplified ratio if 4 : 22 : 30

masya89 [10]

On dividing all the three ratios with 2 u can simplify it as

2:11:15

Hope it helps.
Dont forget to say thx if it helps

6 0

3 years ago

Yesterday Consuela bought some fudge and caramels for $6. She bought 2 pieces of fudge at 50 cents a piece and some caramels at

lana [24]

$\$6-the\ cost\ of\ buying\ candy\\\\2\times\$0.5=\$1-the\ cost\ of\ buying\ fudge\\\\\$6-\$1=\$5-the\ cost\ of\ buying\ caramels\\\\\$5:\$0.25=20-number\ bought \caramels\\\\Consuela\ has\ 10\ caramels,\ so\ Carrie\ has\ 20-10=10-caramels.$

5 0

3 years ago

Read 2 more answers

Constant rate of change = 4<br> Y -intercept = 7

Levart [38]

Answer:

You would write it like -

y = 7 + 4x

or y = 4x + 7

8 0

3 years ago

Read 2 more answers