Answer:
the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
Step-by-step explanation:
From the given question.
Let p be the length of the of the printed material
Let q be the width of the of the printed material
Therefore pq = 2400 cm ²
q = 
To find the dimensions of the poster; we have:
the length of the poster to be p+30 and the width to be 
The area of the printed material can now be: 
=
Let differentiate with respect to p; we have
Also;
For the smallest area 
p² = 3600
p =√3600
p = 60
Since p = 60 ; replace p = 60 in the expression q = to solve for q;
q =
q = 
q = 40
Thus; the printed material has the length of 60 cm and the width of 40cm
the length of the poster = p+30 = 60 +30 = 90 cm
the width of the poster = = 
= 40 + 20 = 60
Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
<span>A is the correct answer. In geometry, postulate is something that is assumed to be true without proof being given. In contrast, a theorem is a true statement which can be proven. A definition defines or explains what a term means. Statement one is a definition of perpendicular lines and statement two can be proven. </span>
22.5/(x-6) + 22.5/(x+6) = 9
multiply by x-6
=> (x-6)22.5/(x-6) + (x-6)22.5/(x+6) = 9(x-6)
=> 22.5 + (x-6)22.5/(x+6) = 9(x-6)
multiply by x+6
=> (x+6)22.5 + (x+6)(x-6)22.5/(x+6) = 9(x-6)(x+6)
=> (x+6)22.5 + (x-6)22.5 = 9(x-6)(x+6)
distribute
=> 22.5x+6(22.5) + 22.5x - 6(22.5) = 9(x^2 - 36)
=> 45x = 9x^2 - 9(36)
=> 0 = 9x^2 - 45x - 9(36)
divide by 9
=> 0 = x^2 - 5x - 36
=> 0 = x^2 - 5x - 36
=> 0 = (x - 9)(x + 4)
x=9 and -4
Answer:
f(x) + g(x) = x² - 10x + 9
General Formulas and Concepts:
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = x² - 11x + 18
g(x) = x - 9
<u>Step 2: Find f(x) + g(x)</u>
- Substitute: f(x) + g(x) = x² - 11x + 18 + x - 9
- Combine like terms (x): f(x) + g(x) = x² - 10x + 9
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Answer:
X<-2
Step-by-step explanation:
