The sum of three consecutive numbers is 90. What is the largest integer?

Catron evaluates the expression (negative 9) (2 and two-fifths) using the steps below.

Vlad [161]

Answer:

Catron's error is

"She did not follow order of operations"

Step-by-step explanation:

Catron evaluates the expression (negative 9) (2 and two-fifths)

That expression can be written as below

$(-9)(2\frac{2}{5})$

Catron's error is

"She did not follow order of operations"

The corrected steps are

Step1: Given expression is $(-9)(2\frac{2}{5})$

Step2: Convert mixed fraction into improper fraction

$(-9)(2\frac{2}{5})=(-9)(\frac{12}{5})$

Step3: Multiplying the terms

$(-9)(2\frac{2}{5})=-7\frac{-108}{5}$

Therefore solution $(-9)(2\frac{2}{5})=-7\frac{-108}{5}$

6 0

3 years ago

Read 2 more answers

Locate the mean of 2046,971,3113,and 1850.

Debora [2.8K]

To find the mean, you have to add all the numbers then divide it by how many numbers there are.

In this case, you'll need to add all those numbers and divide it by 4.
$2046+971+3113+1850=7980\\7980\div4=1995$

The mean is 1995.

7 0

3 years ago

Subtract (4a2b - 3ab2 + 2ab + 5) and (2a2b + 3ab2 - 7ab). Choose the

3241004551 [841]

Answer:

2a2b-6ab2+9ab+5 is right answer

5 0

3 years ago

What is 3 to the sixth power times 3 there is a picture please help worth 12 pts.!!!!!

Diano4ka-milaya [45]

Answer:

2187 ( 3 to the 7th)

Step-by-step explanation:

3 to the 6th= 729

729 x 3 = 2187

6 0

3 years ago

9. Water is added to two containers for 16 minutes. The equations below model the ounces of

Vladimir [108]

The two containers hold 328 ounces at the they hold same amount of water.

<u>Step-by-step explanation:</u>

The equations below model the ounces of water, y, in each container after x minutes.

$y = 16x + 104$

$y = -2x^{2} +40x+160$

At the time after the start when the containers hold the same amount of water, the two equations must be equal.

⇒ $16 x + 104 = -2x^{2} + 40 x + 160$

The first step is to divide everything by 2 to make it simplified.

⇒ $8 x + 52 = - x^2 +20 x + 80$

Now put everything on the left .

$x^2 + 8 x - 20 x + 52 - 80 = 0$

Add the like terms together to further reduce the equation

$x^2 - 12 x - 28 = 0$

Factorizing the equation to find the roots of the equation.

Here, b = -12 and c = -28

where,

b is the sum of the roots ⇒ -14 + 2 = -12
c is the product of the roots ⇒ -14 × 2 = -28

Therefore, (x-14) (x+2) = 0
The solution is x = -2 or x = 14

Take x = 14 and substitute in any of the given two equations,

⇒ $y = 16(14) + 104$

⇒ $y =224+104$

⇒ 328 ounces

∴ The two containers hold 328 ounces at the they hold same amount of water.

5 0

3 years ago