It has to be the last one, D. I did it over 3 times to make sure.
<h2>1)</h2>

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

<h2>2)</h2>
Well he started off correct to the point of completing the square.

Fill your inequality in with the y and x provided and then do the math. (4, -1) would fill in like this (I will use brackets to indicate absolute value symbols, since there are none in the equation editor):
![-1\ \textgreater \ [4]-5](https://tex.z-dn.net/?f=-1%5C%20%5Ctextgreater%20%5C%20%5B4%5D-5)
The right side is in fact equal to the left side so that's not the answer. For (-1, -4):
![-4\ \textgreater \ [-1]-5](https://tex.z-dn.net/?f=-4%5C%20%5Ctextgreater%20%5C%20%5B-1%5D-5)
and these are also equal. Let's try C now (-4, 1):
![1\ \textgreater \ [-4]-5](https://tex.z-dn.net/?f=1%5C%20%5Ctextgreater%20%5C%20%5B-4%5D-5)
. The absolute vale of -4 is 4 so 4 - 5 = -1 which is, in fact, less than 1. So C is our answer.
Answer:
54.
Step-by-step explanation:
The answer is 54.