Answer:
You Will Be Given A Rulebrick and you will have to fill the hole page with things
Step-by-step explanation:
Answer:
<u>The two numbers are 23 and 56</u>
Step-by-step explanation:
Let's say the two numbers are A and B.
We are told:
1) A+B=79
2) 3A+5B=283
Let's take the first expression and solve for A:
A+B=79
A=79-B
Now use this value of A in the second expression:
3A+5B=283
3(79-B)+5B=283
237-3B+5B=283
2B = 46
B = 23
Since B=23, we know from 1) that
A+B=79
A+23=79
A = 56
<u>CHECK:</u>
Does A+B=79?
56+23 = 79? <u>YES</u>
Does 3A+5B=283?
3(56)+5(23)=283
168 + 115 = 283? <u>YES</u>
12. A trapezoid is a quadrilateral. It has 4 sides
16. Two parallelograms. Two sides opposite of each other will be parallel to each other. The same is true with the other two sides. (length and width)
Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
