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RSB [31]
3 years ago
14

A chemist mixed 5 mL of Solution A with every 3 mL of Solution B to make a new solution

Mathematics
1 answer:
Nana76 [90]3 years ago
3 0

Answer:

5:3

Step-by-step explanation:

Given that the chemist mixed 5 mL of Solution A with every 3 mL of Solution B to make a new solution with a new concentration.

So, the amount of Solution A in the mixture, a = 5 mL

The amount of Solution B in the mixture, b = 3 mL

Therefore, the ratio of Solution A to Solution B in the new solution with the same concentration is a:b=5:3.

Hence, the required ratio for the same concentration is 5:3.

Please note that none of the given options matched.

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Step-by-step explanation:

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Evaluate: <br><br> -4/7 (-3/5) (-7/3)
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\text{Hey there!}

-\dfrac{4}{7}(-\dfrac{3}{5})(-\dfrac{7}{3})\\\\-\dfrac{4}{7}\times-\dfrac{3}{5}=\dfrac{12}{35}\\\text{Reason: -4(-3) = 12 \& -7(-5) = 35}\\\\\\\dfrac{12}{35}\times-\dfrac{7}{3} = \text{\bf{ ANSWER}}\\\\\\\dfrac{12}{35}\times-\dfrac{7}{3}=-\dfrac{4}{3}\\\\\\\boxed{\boxed{\text{\bf{Answer}}\bf{\ -\dfrac{4}{5}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

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