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RSB [31]
2 years ago
14

A chemist mixed 5 mL of Solution A with every 3 mL of Solution B to make a new solution

Mathematics
1 answer:
Nana76 [90]2 years ago
3 0

Answer:

5:3

Step-by-step explanation:

Given that the chemist mixed 5 mL of Solution A with every 3 mL of Solution B to make a new solution with a new concentration.

So, the amount of Solution A in the mixture, a = 5 mL

The amount of Solution B in the mixture, b = 3 mL

Therefore, the ratio of Solution A to Solution B in the new solution with the same concentration is a:b=5:3.

Hence, the required ratio for the same concentration is 5:3.

Please note that none of the given options matched.

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lubasha [3.4K]
If there is 2 digits and 7 numbers the combos would be:
1,1 2,1 3,1 4,1 5,1 6,1 7,1
1,2 2,2 3,2 4,2 5,2 6,2 7,2
1,3 2,3 3,3 4,3 5,3 6,3 7,3
1,4 2,4 3,4 4,4 5,4 6,4 7,4
1,5 2,5 3,5 4,5 5,5 6,5 7,5
1,6 2,6 3,6 4,6 5,6 6,6 7,6
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Therefore there are 49 possible combinations :)
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2 years ago
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ss7ja [257]
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5: POSITIVE 3!! again, do the stuff in the parentheses first!! -2-4 is -6. then, -6 x 2 is -12! so, divide -12 by -4 and you get a positive 3!
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