Let O be the center of a circle. If <span>the measure of arc RS is 84 degrees, then m∠SOR=84^{0}. The triangle SOR is isoscales (because SO=OR as radii), so m∠RSO=m∠ORS=(180^{0}-84^{0}):2=48^{0}.
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Line RU is tangent to the circle in point R, this means that m∠ORU=90^{0}.
Consider the triangle SRU. m∠RSU=30^{0} and m∠SRU=48^{0}+90^{0}=138^{0}, then m∠RUS=180^{0}-30^{0}-138^{0}=12^{0}.
ANSWER: Correct choice B - 12^{0}.
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X = u + k
hope this helps & hope I get the brainliest answer
Answer:Coming out like this the normal vectors are going to be parallel to one another. So it's easier for me to test to see whether the normal vectors are parallel.
Step-by-step explanation:
Equilateral, Scalene, Isosceles, Right, acute, obtuse .
What are you asking anyways hope you get a good grade
