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WINSTONCH [101]
2 years ago
5

Choose all correct sentences Group of answer choices The power is maximum when the value of the impedance is greater than the va

lue of the resistance. Resonance occurs when omega squared space equals 1 divided by space L C At resonance, the power is maximum and the impedance is minimum. At resonance, R squared space equals space (X subscript L minus X subscript c )squared The impedance Z is always larger than the resistance R.
Physics
1 answer:
Illusion [34]2 years ago
6 0

Answer:

True  b and c

Explanation:

In an RLC circuit the impedance is

         Z = \sqrt{[R^{2} + ( (wL)^{2} + (\frac{1}{wC})^{2} ]     }

examine the different phrases..

a) False. The maximum impedance is the value of the resistance  

b) True. Resonance occurs when  

              (wL)² + (1 / wC)² = 0

               w² = 1 / LC

c) True. In resonance the impedance is the resistive part and the power is maximum  

d) False. In resonance the inductive and capacitive part cancel each other out  

e) False. The impedance is always greater outside of resonance, but at the resonance point they are equal

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What is 1.2 kg converted into mg.<br> I need to know for step by step please?
astra-53 [7]
Here’s a good photo to reference when converting in the metric system.

Each time you move down a step you move the decimal to the right, each time you move up a step you move the decimal to the left.

We are going from 1.2 kg or kilograms, which is at the very top left of the ladder. To get to mg or milligrams, we would have to make six jumps, so we’d move the decimal over six times.

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4 0
3 years ago
A kangaroo jumps straight up to a vertical height of 1.66 m. How long was it in the air before returning to Earth? Express your
Nataly [62]

Answer:

The kangaroo was 1.164s in the air before returning to Earth

Explanation:

For this we are going to use the equation of distance for an uniformly accelerated movement, that is:

x = x_{0} + V_{0}t + \frac{1}{2}at^2

Where:

x = Final distance

xo = Initial point

Vo = Initial velocity

a = Acceleration

t = time

We have the following values:

x = 1.66m      

xo = 0m (the kangaroo starts from the floor)

Vo = 0 m/s (each jump starts from the floor and from a resting position)

a = 9.8 m/s^2 (the acceleration is the one generated by the gravity of earth)

t =This is just the time it takes to the kangaoo reach the 1.66m, we don't know the value.

Now replace the values in the equation

x = x_{0} + V_{0}t + \frac{1}{2}at^2

1.66 = 0 + 0t + \frac{1}{2}9.8t^2

1.66 = 4.9t^2

\frac{1.66}{4.9}  = t^2

\sqrt{0.339} = t\\ t = 0.582s

It takes to the kangaroo 0.582s to go up and the same time to go down then the total time it is in the air before returning to earth is

t = 0.582s + 0.582s

t = 1.164s

The kangaroo was 1.164s in the air before returning to Earth

5 0
3 years ago
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