<span>82.0 kg
I am going to assume that there is a typo for the number of joules of energy. Doing a google search for this exact question showed this question multiple times with a value of 4942 joules which makes sense given how close the "o" key is to the "9" key. Because of this, I will assume that the correct value for the number of joules is 4942. With that in mind, here's the solution.
The gravitational potential energy is expressed as the mass multiplied by the height, multiplied by the local gravitational acceleration. So:
E = MHA
Solving for M, the substituting the known values and calculating gives:
E = MHA
E/(HA) = M
4942/(6.15*9.8) = M
4942/60.27 = M
81.99767712 = M
Rounding to 3 significant figures gives 82.0 kg</span>
Answer:
Vdc=10V
Explanation:
in a closed loop consisting of a super charged capacitor and an inductor, the super charge capacitor acts as a supply when the loop is closed, at t=0, the emf stored in the capacitor is 10V (q/c); and at that same time Vl= voltage across the inductor or loop too would be 10V,
if the loop remains closed for a longer period, the inductor would absorb energy from the capacitor till it dissipates all charges with itself.
The <u>average</u> acceleration for an object undergoing this change in velocity is
(12.5 m/s - 8.3 m/s) / (1.24 s) = (4.2 m/s) / (1.24 s) ≈ 3.4 m/s²
A sphere is charged with electrons to −9 × 10−6 C. The value given is the total charge of all the electrons present in the sphere. To calculate the number of electrons in the sphere, we divide the the total charge with the charge of one electron.
N = 9 × 10−6 C / 1.6 × 10−19 C
N = 5.6 x 10^13
