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Katarina [22]
2 years ago
5

How do i find acceleration due to gravitational force?

Physics
1 answer:
Alexxandr [17]2 years ago
6 0

Answer:

a = 9.8 m/s²

Explanation:

Acceleration due to gravity on Earth is constant, which is 9.8 m/s²

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When will an object sink in water, according to Archimedes' principle?​
inna [77]

Answer:

If the buoyant force is greater than the object's weight, the object will rise to the surface and float. If the buoyant force is less than the object's weight, the object will sink. If the buoyant force equals the object's weight, the object will remain suspended at that depth.

Explanation:

Not much explaining to do here!

7 0
3 years ago
compare to visible light, the wavelength of x-rays is shorter longer or the same and the frequency is lower higher or the same
Doss [256]

Answer:shorter higher

Explanation:Compare to visible light, the wavelength of X-rays is shorter and then frequency is higher

7 0
3 years ago
Explain how gravity and friction work to slow down a kicked soccer ball.
goblinko [34]
Use your feet to stop it since it is soccer you can't use your hands!!!! P.S. you can't use gravity.

5 0
3 years ago
Jenny must do her part to make sure her work environment is safe. Which of the following behaviors will help keep her and her co
siniylev [52]
The <span> behaviors will help keep her and her co-workers safe are:

</span><span>- Be familiar with her employer’s workplace violence policy. (so they could operate within the safety guideline)</span>

<span>-. Report any warning signs or threats of violence. (better be cautious than sorry)</span>

<span>- Treat co-workers and customers with respect.(to prevent any potential conflicts that could lead to violence)</span>
8 0
3 years ago
A transformer connected to a 120-v(rms) at line is to supply 13,000V(rms) for a neon sign.
lyudmila [28]

Answer:

(a) 108

(b) 110.500 kW

(c) 920.84 A

Solution:

As per the question:

Voltage at primary, V_{p} = 120\ V          (rms voltage)

Voltage at secondary, V_{s} = 13000\ V  (rms voltage)

Current in the secondary, I_{s} = 8.50\ mA  

Now,

(a) The ratio of secondary to primary turns is given by the relation:

\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{s}}

where

N_{p} = No. of turns in primary

N_{s} = No. of turns in secondary

\frac{N_{s}}{N_{p}} = \frac{13000}{120} ≈ 108

(b) The power supplied to the line is given by:

Power, P = V_{s}I_{s} = 13000\times 8.50 = 110.500\ kW

(c) The current rating that the fuse should have is given by:

\frac{V_{s}}{V_{p}} = \frac{I_{p}}{I_{s}}

\frac{13000}{120} = \frac{I_{p}}{8.50}

I_{p} = \frac{13000}{120}\times 8.50 = 920.84\ A

 

6 0
3 years ago
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