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Dominik [7]
3 years ago
10

Do changes that cannot be easily reversed, such a burning, observe the law of conservation of mass? Explain.

Physics
2 answers:
andreev551 [17]3 years ago
6 0

yes!!! Everything follows the law of

conservation of mass, no matter what

artcher [175]3 years ago
4 0

Answer:

Yes

Explanation:

According to law of conservation of mass, it can neither be created or destroyed. It remains constant. It can change to energy. This can be explained using Einstein's mass energy relation. E= mc^2.

So, the changes such as burning cannot be reversed do obey law of conservation of mass. Suppose wood is burnt. The mass of wood converts into energy and ashes.

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Estimate the mass of water that must evaporate from the skin to cool the body by 0.45 ∘C. Assume a body mass of 95 kg and assume
hram777 [196]

Answer:

0.0757 kg

Explanation:

m = mass of the body = 95 kg = 95000 g

ΔT = change in the temperature of the body = 0.45 °C

c = specific heat capacity of the body = 4.0 J/(g °C)

M = mass of water evaporated

L = latent heat of vaporization of water = 2260 J/g

Using conservation of heat

Heat gained by water = heat lost by body

ML = m c ΔT

M (2260) = (95000) (4.0) (0.45)

M = 75.7 g

M = 0.0757 kg

4 0
3 years ago
Wave 1 displaces according the function f(θ)= 2sin θ+1. Wave 2 displaces according to the function f(θ)= 3sin θ+.5. At what angl
r-ruslan [8.4K]

Answer:

θ = 30⁰  

Explanation:

We have been given two wave displacement equations,

y_{1} =2sin\theta +1     ........(1)

y_{2}=3sin\theta +0.5     ........(2)

The waves will have same displacements when y_{1}=y_{2}=y (say)

Therefore, operating (2) - (1), we get,

sin\theta - 0.5=0

or, \theta = sin^{-1}(0.5)=30^{o} (since, sin 30⁰ = 0.5)

We can check the answer by putting \theta=30^{o} in equations (1) and (2),

y_{1}=2sin30^{o}+1=2\times0.5 + 1= 2

y_{2}=3sin30^{o}+0.5=3\times0.5+0.5=1.5+0.5=2

6 0
3 years ago
Read 2 more answers
A car is moving on the distance 35km in the time 30minutes,stays 20 minutes,the it moves again vith the velocite 60km/h in 25 mi
FinnZ [79.3K]
Velocity = distance/time
v = (35)/(1/2)
v = 70 km/h


60 km/h for 25 minutes
25 minutes = 25/60 hour
    distance= velocity * time
d =(60) * (25/60)
d = 25 km

ΔV = { V(initial) - V(final) } / time
v= (70-60) / (45/60)
average velocity = 13.33 km/h
avg veloticy = 3.7 m/s

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8 0
3 years ago
HELP!!!What type of image is formed by a lens if m=-0.87?
lara31 [8.8K]
Ur asnwers B my friend have an amazing day:)
7 0
3 years ago
Read 2 more answers
(a) Suppose that your measured weight at the equator is one-half your measured weight at the pole on a planet whose mass and dia
stealth61 [152]

Answer:

7160.2812 s or 1.988 hours

Explanation:

m = Mass of person

R = Radius of Earth = 6.37\times 10^{6}\ m

g = Acceleration due to gravity = 9.81 m/s²

\omega = Angular speed

Force at equator would be

F_e=m(g-\omega^2R)

Force at pole

F_p=mg

From the question

F_e=\dfrac{1}{2}F_p\\\Rightarrow m(g-\omega^2R)=\dfrac{1}{2}F_p\\\Rightarrow \omega=\sqrt{\dfrac{g}{2R}}

Time period is given by

T=\dfrac{2\pi}{\omega}\\\Rightarrow T=2\pi\sqrt{\dfrac{2R}{g}}\\\Rightarrow T=2\pi\sqrt{\dfrac{2\times 6.37\times 10^6}{9.81}}\\\Rightarrow T=7160.2812\ s=1.988\ hours

The rotational period of the planet is 7160.2812 s or 1.988 hours

5 0
3 years ago
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