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Dominik [7]
3 years ago
10

Do changes that cannot be easily reversed, such a burning, observe the law of conservation of mass? Explain.

Physics
2 answers:
andreev551 [17]3 years ago
6 0

yes!!! Everything follows the law of

conservation of mass, no matter what

artcher [175]3 years ago
4 0

Answer:

Yes

Explanation:

According to law of conservation of mass, it can neither be created or destroyed. It remains constant. It can change to energy. This can be explained using Einstein's mass energy relation. E= mc^2.

So, the changes such as burning cannot be reversed do obey law of conservation of mass. Suppose wood is burnt. The mass of wood converts into energy and ashes.

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A student decides to spend spring break by driving 50 miles due east, then 50 miles 30 degrees south of east, then 50 miles 30 d
PolarNik [594]

Answer:

a. 600 ml, 12

Explanation:

The movement described in the question exhibits that of a polygon. Exhibiting a constant distance and angle with only varying direction until the starting point is reached.

The sum of exterior angles of a polygon = 360 degrees.

Exterior angle of a polygon = (360 ÷ number of sides)

Therefore,

Number of sides = 360 ÷ exterior angle

Exterior angle = 30 degrees

Hence,

Number of sides = 360 ÷ 30 = 12 sides

Since distance traveled of 50 miles is the same for each displacement ;

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4 years ago
Why is temperature constant during a phase change?
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to

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7 0
3 years ago
1) A football player kicks a ball at an angle of 30 and gives it a velocity of 15m/s.
mote1985 [20]

Answer:

A) 1.53s

B) 19.8m

C) 2.869m

Explanation:

A) The time of flight for a projectile can be calculated using the formula:

t = 2μsinθ/g

Where; u = velocity

θ = angle

g = acceleration due to gravity (9.8m/s^2)

t = 2 × 15 × sin 30°/9.8

t = 30sin30°/9.8

t = 30 × 0.5/9.8

t = 15/9.8

t = 1.53s

B) The horizontal range (distance) for a projectile can be calculated using the formula:

Range = u²sin2θ/ g

Range = 15² sin 2 × 30 / 9.8

Range = 225 sin 60/9.8

Range = 225 × 0.8660/9.8

Range = 194.855/9.8

Range = 19.8m

C) The maximum height for a projectile can be calculated using the formula:

h = u²sin²θ/2g

h = 15² (sin 30)² / 2 × 9.8

h = 225 × 0.25 / 19.6

h = 56.25/19.6

h = 2.869m

​

3 0
4 years ago
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