All categories

3 years ago

When is the kinetic energy of an electron transformed into potential energy?

Physics

1 answer:

8090 [49]3 years ago

4 0

Answer:

when it interacts with other electrons without changing its speed

Explanation:

without changing its speed

You might be interested in

Use the crisscross method to find the chemical formula for the ionic compound formed by strontium (Sr) and bromine (Br).

nignag [31]

Answer:it’s c SrBr2

Explanation:

8 0

3 years ago

Read 2 more answers

A clock which has brass pendulum beats seconds correctly when the temperature of the room is 30° C. how many seconds will it gai

Andrei [34K]

Answer:A::C

Solution :

ΔT=

TαΔθ

rArr Δt=

ΔT

T1t

But T′≈T

∴Δt=

αΔθ(t)

×0.000012×20×24×3600

=10.37s

At higher temperture, length of pendulum clock will be more. So, time period will be more and it will lose the time.

Explanation:

7 0

3 years ago

Discuss the law of conservation of energy. Provide at least one example that supports your description.

stich3 [128]

the law of conservation of energy states that the total energy of an isolated system remains constant it would be said to be conserved over time. Energy can neither be created nor destroyed but then rather, it transforms from one form to another.

hope this can help you ^_^

3 0

3 years ago

A body of mass 500g accelerates at a rate of 5 metres per second square. Calculate the force applied to the body

kenny6666 [7]

Answer:

2.5 N

Explanation:

F = m•a

F = 0.5•5

F = 2.5 N

5 0

3 years ago

Suppose a uniform electric field of 4N/C is in the positive x direction. When a charge is placed and at a fixed to the origin, t

Levart [38]

Answer:

3N/C

Explanation:

Thinking process:

Let, electric field of 4N/C is in the positive x direction, that is + 4 NC

And the the resulting electric field on the x axis at x =2m

Therefore, based on the data above, the net charge must be in the positive direction. Thus, the magnitude is given by the equation:

$q = \frac{Er^{2} }{k} \\ = \frac{4 (4)}{9*10^{4} } \\ = \frac{16}{9}NC$

Now considering that at x = + 4 NC, the net charge will be:

$E_{net} = E_{0} + E_{q} \\ = 4 -(\frac{9*10^{} }{16}*\frac{16}{9} * 10^{-90})\\ = 3 (N/C)$

4 0

3 years ago