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The graph represents velocity over time. What is the acceleration? –0.4 m/s2 –0.2 m/s2 0.2 m/s2 0.4 m/s2

Olenka [21]

Missing graph. I attach it in the answer.

In a uniformly accelerated motion, the velocity at time t is given by:
$v(t)=at$
where a is the acceleration and t is the time.

Given the previous equation, if we plot v(t) versus t, we find a straight line; moreover, a (the acceleration) represents the slope of the curve.

Looking at the graph, we see that when the time goes from 10 s to 20 s, the velocity increases from 4 m/s to 6 m/s. Therefore the slope of the curve is
$a= \frac{\Delta v}{\Delta t}= \frac{6 m/s-4 m/s}{20 s-10 s}= \frac{2 m/s}{10 s}=0.2 m/s^2$
and this corresponds to the acceleration.

So, the correct answer is <span>0.2 m/s2.</span>

7 0

3 years ago

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If the skater coasts only around 65 degrees of the circle, find the magnitude of his displacement vector.

baherus [9]

We are given a skater who coasts only around 65 degrees of the circle. The magnitude of the vector is determined by converting 65 degrees to radians:

65//180 = 0.36 radians

The displacement of the vector is 65 degrees east.

4 0

4 years ago

Who pioneered the use of galvanoplastic compounds for preserving footprints and ballistics?

alukav5142 [94]

Answer:

Option D (Alphonse Bertillon) is the correct response.

Explanation:

He seems to have been a policeman turned biometrics expert from France. Forensic techniques such as forensic record analysis were developed by Bertillon.
To retain proof, he always pioneered or developed the use of such galvanoplastic compounds as molds for footsteps as well as ballistics. To research physical changes with age, Bertillon has developed a method focused on images of almost the same person’s performance.

All those other choices weren’t connected to the instance offered. So, the best one is the one described.

5 0

3 years ago

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The electric field strength E is measured as:

soldi70 [24.7K]

The correct answer is
<span>force per unit charge.

In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span> $E= \frac{F}{q}$
where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.

4 0

3 years ago

A block of mass M is attached to a spring of negligible mass and can slide on a horizontal surface along the x-direction, as sho

Hoochie [10]

Answer:

Because of the frictional force, the net force will oppose direction of the block and be directed towards the left even tho the spring exerts no force at this point

6 0

3 years ago