These states ofwater are simply physical changes. It has stayed the compound H2O throughout all of them. It had changes in phases but it never changed to anything but water.
Answer:
138,516,546.9 horas.
Explanation:
Tenemos que usar la ecuación:
Velocidad = distancia/tiempo
Acá tenemos:
Velocidad = 0.3m/s
distancia = 149597870700 m
y queremos resolver la ecuación para el tiempo:
0.3m/s = 149597870700m/tiempo.
tiempo = 149597870700m/(0.3m/s) = 498,659,569,000 s
y sabemos que una hora tiene 3600 segundos, entonces si queremos transformar de segundos a horas tenemos:
498,659,569,000 s = (498,659,569,000/3600) h = 138,516,546.9 horas.
Answer:
Call the parent's for the safety of the baby
Explanation:
W=2485.65 J ,work did the movers do friction force a 41.0- kg crate 10.3 m across a rough floor without acceleration
<h3>What is a basic friction force?</h3>
Two surfaces that come into contact and slide against one another produce a force known as frictional force. Several aspects that influence the frictional force include: The surface texture as well as the amount of force attracting them together have the most effects on these forces.
<h3>What outcomes does friction produce?</h3>
It generates heat, which is useful for warming our bodies or specific areas of any object. Power is also lost as a result. It makes noise during every operation. We are able to walk, run, dance, etc. due to friction.
To know more about friction force visit:
brainly.com/question/1389727
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Answer:
The magnitude and direction are
7.638×10-4m
80.01°
Explanation:
We know that the coefficient of linear expansion for copper = 16.6×10^-6 m/m-C
ΔT = 40.2 - 18.0 = 28.5 C°
The expansion of horizontal pipe length can be calculated as
= (0.28)(16.6×10^-6)(28.5) = 13247×10^-8
= 0.0001325 m
The expansion of vertical pipe length = (1.28)(16.6×10^-6)(28.5) = 60557×10^-8 = 0.000752229 m
horizontal displacement = 0.1325 mm
= 1.356×10^-4m
vertical displacement = 0.75223mm
=7.5223×10-4m
size of total displacement can be calculated as
√(x²+y²)
Where x and y are vertical and horizontal displacement respectively
= √(0.1325)²+(0.75223)² =
= 0.7638 mm
= 7.638×10-4m
Angle below horizontal = arctan Θ
= 0.75223/0.1325
=5.6772
= arctan (5.6772)
= 80.01°
Therefore, the the magnitude and direction of the displacement of the pipe elbow when the water flow is turned at (7.638×10-4m) 0.7638 mm and 80.01°
